Sql 我有一个带有列图像路径的表，我需要从字符串中生存

图像路径及其列名

我想从IMAGE_PATH列获取子字符串，如下所示

表示我需要介于最后一个“/”之后和之前的子字符串 请为我提供解决方案，它将如何修复

尝试以下简单方法使用SUBSTR和INSTR：

编辑：如果您不想使用获取文件扩展名。使用：

输出：

尝试以下简单方法使用SUBSTR和INSTR：

编辑：如果您不想使用获取文件扩展名。使用：

输出：

---

您可以尝试以下方法：

WITH d1 AS (
    SELECT 'sph/images///////30_Fairhall_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images///8_Furnival_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images/9_Pennethorne_House.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'rbkc/images/TAVISTOCK_CRESCENT.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'haringey///images/399932thumb.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'urbanchoice/images//18190862.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'westminster/images//7_Glarus_Court.jpeg' AS image_path FROM dual
)
SELECT TRIM(TRAILING '.' FROM REGEXP_SUBSTR(image_path, '[^/]+\.'))
  FROM d1;

以上假设不存在。最后一个/前面的字符。更好的解决方案可能是：

WITH d1 AS (
    SELECT 'sph/images///////30_Fairhall_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images///8_Furnival_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images/9_Pennethorne_House.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'rbkc/images/TAVISTOCK_CRESCENT.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'haringey///images/399932thumb.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'urbanchoice/images//18190862.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'westminster/images//7_Glarus_Court.jpeg' AS image_path FROM dual
)
SELECT REGEXP_SUBSTR(image_path, '[^.]+', INSTR(image_path, '/', -1) + 1) 
  FROM d1;

也就是说，查找所有非-。请注意，逃逸。在字符类中，final/之后的字符不需要

输出：

30_Fairhall_Court
8_Furnival_Court
9_Pennethorne_House
TAVISTOCK_CRESCENT
399932thumb
18190862
7_Glarus_Court

---

您可以尝试以下方法：

WITH d1 AS (
    SELECT 'sph/images///////30_Fairhall_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images///8_Furnival_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images/9_Pennethorne_House.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'rbkc/images/TAVISTOCK_CRESCENT.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'haringey///images/399932thumb.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'urbanchoice/images//18190862.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'westminster/images//7_Glarus_Court.jpeg' AS image_path FROM dual
)
SELECT TRIM(TRAILING '.' FROM REGEXP_SUBSTR(image_path, '[^/]+\.'))
  FROM d1;

以上假设不存在。最后一个/前面的字符。更好的解决方案可能是：

WITH d1 AS (
    SELECT 'sph/images///////30_Fairhall_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images///8_Furnival_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images/9_Pennethorne_House.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'rbkc/images/TAVISTOCK_CRESCENT.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'haringey///images/399932thumb.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'urbanchoice/images//18190862.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'westminster/images//7_Glarus_Court.jpeg' AS image_path FROM dual
)
SELECT REGEXP_SUBSTR(image_path, '[^.]+', INSTR(image_path, '/', -1) + 1) 
  FROM d1;

也就是说，查找所有非-。请注意，逃逸。在字符类中，final/之后的字符不需要

输出：

30_Fairhall_Court
8_Furnival_Court
9_Pennethorne_House
TAVISTOCK_CRESCENT
399932thumb
18190862
7_Glarus_Court

---

单斜杠、双斜杠或三斜杠您的数据有三个斜杠，可能有很多次，但我需要最后一次出现“/”和点之前的结果。@Ameya Deshpande:-它给出了无效的左标识符。是的，这是特定于sqlserver的。我没有识别您的Oraclegexp_substr'/sfs/sfsf/file_name.jpeg'/[^./]+[.]jpg | jpeg | png | bmp | gif$，1,1，NULL，1a单斜杠或双斜杠或三斜杠您的数据有三个可能有很多次，但我需要上次出现“/”和点之前的结果。@Ameya Deshpande:-它给出的左标识符无效。是的，这是特定于sqlserver的。我没有识别您的Oraclegexp_substr'/sfs/sfsff/file_name.jpeg'，“/[^./]+[.]jpg | jpg | png | bmp | gif$”，1,1，空，1

WITH d1 AS (
    SELECT 'sph/images///////30_Fairhall_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images///8_Furnival_Court.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'sph/images/9_Pennethorne_House.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'rbkc/images/TAVISTOCK_CRESCENT.jpeg' AS image_path FROM dual
     UNION ALL
    SELECT 'haringey///images/399932thumb.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'urbanchoice/images//18190862.jpg' AS image_path FROM dual
     UNION ALL
    SELECT 'westminster/images//7_Glarus_Court.jpeg' AS image_path FROM dual
)
SELECT REGEXP_SUBSTR(image_path, '[^.]+', INSTR(image_path, '/', -1) + 1) 
  FROM d1;

30_Fairhall_Court
8_Furnival_Court
9_Pennethorne_House
TAVISTOCK_CRESCENT
399932thumb
18190862
7_Glarus_Court