Oracle SQL有助于以两种不同的方式计算同一事物，但有共同的分组

我有一个表，每个条目都包含一个事件id、状态（比如打开或关闭）、日期、提出日期和结束日期

我想显示一个统计在关闭日期关闭的事件数的表，以便status='closed'和closed_date处的事件\u id计数不为空，以及在同一天status='open'处的事件\u id计数保持打开的事件数

如果我把你弄糊涂了，一张像这样的桌子：

 ______________________________________________________________________________
| closure date | count of incidents closed | count of incidents remaining open |
|--------------|---------------------------|-----------------------------------|
| 01-Sep-12    | 5                         | 14                                |
| ...          | ...                       | ...                               |

SELECT COUNT(incident_id)
WHERE closure_date IS NOT NULL AND status="open"
GROUP BY closure_date

SELECT 
closure_date,
SUM(CASE WHEN status="open" 
         THEN 1 ELSE 0 END) AS "count of incidents open",
SUM(CASE WHEN  status="closed" 
         THEN 1 ELSE 0 END) AS "count of incidents closed"
FROM YourTable
WHERE closure_date IS NOT NULL
GROUP BY closure_date

SELECT t1.closure_date, COUNT(t1.incident_id)
     , ( SELECT COUNT(t2.incident_id) FROM incident_table t2
          WHERE t2.status = 'open'
            AND t2.raised_date < t1.closure_date )
  FROM incident_table t1
 WHERE t1.closure_date IS NOT NULL
   AND t1.status = 'closed'
 GROUP BY t1.closure_date

我管理了一个表，该表可以计算这样结束的事件数：

 ______________________________________________________________________________
| closure date | count of incidents closed | count of incidents remaining open |
|--------------|---------------------------|-----------------------------------|
| 01-Sep-12    | 5                         | 14                                |
| ...          | ...                       | ...                               |

SELECT COUNT(incident_id)
WHERE closure_date IS NOT NULL AND status="open"
GROUP BY closure_date

SELECT 
closure_date,
SUM(CASE WHEN status="open" 
         THEN 1 ELSE 0 END) AS "count of incidents open",
SUM(CASE WHEN  status="closed" 
         THEN 1 ELSE 0 END) AS "count of incidents closed"
FROM YourTable
WHERE closure_date IS NOT NULL
GROUP BY closure_date

SELECT t1.closure_date, COUNT(t1.incident_id)
     , ( SELECT COUNT(t2.incident_id) FROM incident_table t2
          WHERE t2.status = 'open'
            AND t2.raised_date < t1.closure_date )
  FROM incident_table t1
 WHERE t1.closure_date IS NOT NULL
   AND t1.status = 'closed'
 GROUP BY t1.closure_date

我已经试了几个小时让另一个计数工作，但到目前为止还不能：-

编辑：以下是我的表格示例：

 ___________________________________________________
| incident_id | status | date_raised | closure_date |
|-------------|--------|-------------|--------------|
| 1           | closed | 01-Sep-12   | 01-Sep-12    |
| 2           | open   | 30-Aug-12   | (null)       |
| 3           | open   | 02-Sep-12   | (null)       |
| 4           | closed | 02-Sep-12   | 05-Sep-12    |
| ...         | ...    | ...         | ...          |

我将向各位介绍：

 ______________________________________________________________________________
| closure date | count of incidents closed | count of incidents remaining open |
|--------------|---------------------------|-----------------------------------|
| 01-Sep-12    | 1                         | 1                                 |
| 05-Sep-12    | 1                         | 2                                 |

---

您应该尝试以下方法：

 ______________________________________________________________________________
| closure date | count of incidents closed | count of incidents remaining open |
|--------------|---------------------------|-----------------------------------|
| 01-Sep-12    | 5                         | 14                                |
| ...          | ...                       | ...                               |

SELECT COUNT(incident_id)
WHERE closure_date IS NOT NULL AND status="open"
GROUP BY closure_date

SELECT 
closure_date,
SUM(CASE WHEN status="open" 
         THEN 1 ELSE 0 END) AS "count of incidents open",
SUM(CASE WHEN  status="closed" 
         THEN 1 ELSE 0 END) AS "count of incidents closed"
FROM YourTable
WHERE closure_date IS NOT NULL
GROUP BY closure_date

SELECT t1.closure_date, COUNT(t1.incident_id)
     , ( SELECT COUNT(t2.incident_id) FROM incident_table t2
          WHERE t2.status = 'open'
            AND t2.raised_date < t1.closure_date )
  FROM incident_table t1
 WHERE t1.closure_date IS NOT NULL
   AND t1.status = 'closed'
 GROUP BY t1.closure_date

---

在我看来，对于每个日期，您都希望获得迄今为止已关闭的问题的数量，以及在该日期之前提出的尚未解决的问题的数量，对吗？所以你可能想要这样的东西：

 ______________________________________________________________________________
| closure date | count of incidents closed | count of incidents remaining open |
|--------------|---------------------------|-----------------------------------|
| 01-Sep-12    | 5                         | 14                                |
| ...          | ...                       | ...                               |

SELECT COUNT(incident_id)
WHERE closure_date IS NOT NULL AND status="open"
GROUP BY closure_date

SELECT 
closure_date,
SUM(CASE WHEN status="open" 
         THEN 1 ELSE 0 END) AS "count of incidents open",
SUM(CASE WHEN  status="closed" 
         THEN 1 ELSE 0 END) AS "count of incidents closed"
FROM YourTable
WHERE closure_date IS NOT NULL
GROUP BY closure_date

SELECT t1.closure_date, COUNT(t1.incident_id)
     , ( SELECT COUNT(t2.incident_id) FROM incident_table t2
          WHERE t2.status = 'open'
            AND t2.raised_date < t1.closure_date )
  FROM incident_table t1
 WHERE t1.closure_date IS NOT NULL
   AND t1.status = 'closed'
 GROUP BY t1.closure_date

---

嗯，事实上不太清楚，也许：你的表的主键是什么？事故识别码？意味着事件不能有两种状态？或也许真正的表结构或一些示例数据会有所帮助…@Raphael incident_id是主键。该表包含事件id、提出日期、结束日期和状态。因此，如果状态为“打开”，则关闭日期将为空。如果状态为关闭，则将有一个关闭日期。下面的解决方案没有显示给定关闭日期当天或之前的开放事件数量，但显示了关闭日期上的关闭数量date@RaphaëlAlthaus我在问题中添加了一个数据示例表OK，编辑了我的答案，应该会更好。顺便说一下，我删除了闭包日期不是空测试，因为我认为关闭状态意味着关闭日期不是空的，而是关闭的，但是打开计数不仅需要状态=“打开”，而且还需要以某种方式提出的日期<[集团的关闭日期]，我不知道这是否可能：-S@BenHill对完成。哦，好吧，烧焦了；不幸的是，你被打败了但我离得很近@本希尔，如果你觉得我的回答有帮助的话，也请投赞成票。谢谢我一到15点就来P