Sql OrderBy日期，但包含前一天“半天”的记录

日期：行积压：数量积压

2015-09-20:10:50

2015-09-21:5:25

这里的问题是当我们到达第二天。。。如果订单在2015-09-21 12:00之后完成，21将获得更多记录

当我们运行此程序时，只需将前一天12:00之前的记录按日期分组即可

我的问题是。。

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我想显示2015-09-22的日期，并在2015-09-21的12:00之后到2015-09-22的12:00之前保留记录。。。所以这应该是可行的。它先将注册日期移动12小时

SELECT cast(Ord.regdate AS date) AS Date,
       COUNT(Ord.Ordernumber) AS [Backlog of line],

  (SELECT CASE
              WHEN CAST(SUM(Ord.Qty) AS INT) IS NULL THEN 0
              ELSE CAST(SUM(Ord.Qty) AS INT)
          END) AS [Backlog of Qty]
FROM Orders [Ord]
WHERE Ord.regdate < CAST(CAST(CAST(DATEADD(DAY,-1,GETDATE()) AS date) AS varchar(10)) + ' 12:00' AS datetime)
GROUP BY cast(Ord.regdate AS date)
ORDER BY cast(Ord.regdate AS date) DESC    

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构建一个视图，使用半天规则获取3列：RegDate date、RegDateFrom datetime、RegDateTo datetime，加入RegDateFrom和RegDateTo上的订单，然后按RegDate分组。谢谢，这是一个prod服务器，因此在没有它们的情况下无法创建新视图或表。如果有人有其他修复程序，请告诉我使用CTE不需要是物理视图

SELECT Ord.regdate AS Date,
       COUNT(Ord.Ordernumber) AS [Backlog of line],

  (SELECT CASE
              WHEN CAST(SUM(Ord.Qty) AS INT) IS NULL THEN 0
              ELSE CAST(SUM(Ord.Qty) AS INT)
          END) AS [Backlog of Qty]
FROM (
    Select Ordernumber, Qty, CAST(DATEADD(HOUR, 12, regdate) as date) as regdate
    From Orders 
    WHERE regdate < CAST(CAST(CAST(DATEADD(DAY,-1,GETDATE()) AS date) AS varchar(10)) + ' 12:00' AS datetime)
) [Ord]
GROUP BY Ord.regdate
ORDER BY Ord.regdate DESC