选择SQL中不连续出现的所有人员

我有以下内容的人员表：

year    name
2015    John
2016    John
2017    John
2015    Mary
2015    Jennifer
2016    Jennifer
2015    Lisa
2016    Lisa
2017    Lisa

我怎样才能得到所有这些年来没有持续出现的人

答案应该是：

2015    Mary
2015    Jennifer
2016    Jennifer

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一种方法是按名称聚合，然后断言给定名称的不同年数不等于整个表中的总不同年数

SELECT t1.name
FROM yourTable t1
INNER JOIN
(
    SELECT name
    FROM yourTable
    GROUP BY name
    HAVING COUNT(DISTINCT year) < (SELECT COUNT(DISTINCT year) FROM yourTable)
) t2
     ON t1.name = t2.name
ORDER BY
    t1.name,
    t1.year;

---

一种方法是按名称聚合，然后断言给定名称的不同年数不等于整个表中的总不同年数

SELECT t1.name
FROM yourTable t1
INNER JOIN
(
    SELECT name
    FROM yourTable
    GROUP BY name
    HAVING COUNT(DISTINCT year) < (SELECT COUNT(DISTINCT year) FROM yourTable)
) t2
     ON t1.name = t2.name
ORDER BY
    t1.name,
    t1.year;

---

您可以使用下面的查询

select * from persons p1
where exists
(select name, count(1) from persons p2 where p1.name=p2.name group by name having count(1) <
(select count(distinct year) from persons));

---

您可以使用下面的查询

select * from persons p1
where exists
(select name, count(1) from persons p2 where p1.name=p2.name group by name having count(1) <
(select count(distinct year) from persons));

---

您可以使用以下查询：

---

您可以使用以下查询：

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我建议使用窗口功能。假设每个名称没有重复项：

select p.*
from (select p.*,
             count(*) over (partition by name) as cnt_name,
             count(distinct year) over () as cnt_years
      from persons p
     ) p
where cnt_name <> cnt_years;

---

我建议使用窗口功能。假设每个名称没有重复项：

select p.*
from (select p.*,
             count(*) over (partition by name) as cnt_name,
             count(distinct year) over () as cnt_years
      from persons p
     ) p
where cnt_name <> cnt_years;

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如果2016年没有人在场怎么办？列出每一个人或考虑今年无关？每个人都应该出现在2015至2017年如果没有人出现在2016？列出每一个人或考虑今年无关？每个人都应该出现在2015至2017年。