Sql 如何在视图表中包括分组依据
我有以下脚本Sql 如何在视图表中包括分组依据,sql,oracle,Sql,Oracle,我有以下脚本 drop view proba; create view proba as select distinct oper as p_name , sum(duration) as out_duration from TA_OUT where oper in ('CZE','FRA') and timestamp like '201306%' group by oper; drop view proba1; create view proba1 as select distinc
drop view proba;
create view proba as
select distinct oper as p_name
, sum(duration) as out_duration
from TA_OUT
where oper in ('CZE','FRA')
and timestamp like '201306%'
group by oper;
drop view proba1;
create view proba1 as
select distinct oper as p_name
,sum(duration) as in_duration
from TA_IN
where oper in ('CZE','FRA')
and timestamp like '201306%'
group by oper;
drop view proba3;
create view proba3 as
select distinct oper as p_name
,sum(duration) as out_duration
from TA_OUT
where oper in ('CZE','FRA')
and timestamp like '201305%'
group by oper;
drop view proba4;
create view proba4 as
select distinct oper as p_name
,sum(duration) as in_duration
from TA_IN
where oper in ('CZE','FRA')
and timestamp like '201305%'
group by oper;
drop view proba2;
create view proba2 as
select distinct oper as p_name
from OPER_DESCRIPTION;
此代码的思想是接收不同月份的持续时间,然后在下一个代码中比较此持续时间。这是下一个代码
drop view proba5;
CREATE VIEW proba5 AS
SELECT (BAL1 + BAL2) AS BAL
FROM
(
SELECT
CASE
WHEN proba.out_duration <= proba1.in_duration
AND proba.p_name IN ('CZE', 'FRA')
AND proba1.p_name IN ('CZE', 'FRA')
THEN (proba.out_duration / 60) * 0.14
WHEN proba.out_duration > proba1.in_duration
AND proba.p_name IN ('CZE', 'FRA')
AND proba1.p_name IN ('CZE', 'FRA')
THEN
(proba1.in_duration / 60) * 0.14
+
((proba.out_duration - proba1.in_duration) / 60) * 0.09
ELSE 0
END AS BAL1
, CASE
WHEN proba3.out_duration <= proba4.in_duration
AND proba3.p_name IN ('CZE', 'FRA')
AND proba4.p_name IN ('CZE', 'FRA')
THEN (proba3.out_duration / 60) * 0.14
WHEN proba3.out_duration > proba4.in_duration
AND proba3.p_name IN ('CZE', 'FRA')
AND proba4.p_name IN ('CZE', 'FRA')
THEN
(proba4.in_duration / 60) * 0.14
+ ((proba3.out_duration - proba4.in_duration) / 60) * 0.09
ELSE 0
END AS BAL2
FROM
(
(
(
(
proba2
LEFT JOIN proba
ON proba2.p_name = proba.p_name
)
LEFT JOIN proba1
ON proba1.p_name = proba1.p_name
LEFT JOIN proba3
ON proba3.p_name = proba3.p_name
)
LEFT JOIN proba4
ON proba4.p_name = proba4.p_name
)
WHERE proba.p_name IN ('CZE', 'FRA')
AND proba1.p_name IN ('CZE', 'FRA')
AND proba3.p_name IN ('CZE', 'FRA')
AND proba4.p_name IN ('CZE', 'FRA')
)
);
然而,问题是我不能只按p_名称分组,因为我也应该按持续时间分组 您能告诉我如何解决这个问题吗。请查看此问题:
CREATE VIEW proba5
AS
SELECT p_name, SUM(BAL1 + BAL2)
FROM (
SELECT
proba.p_name,
CASE
WHEN proba.out_duration <= proba1.in_duration
THEN proba.out_duration / 60) * 0.14
WHEN proba.out_duration > proba1.in_duration
THEN (proba1.in_duration / 60) * 0.14
+ ((proba.out_duration - proba1.in_duration)/60) * 0.09
ELSE 0
END AS BAL1,
CASE
WHEN proba3.out_duration <= proba4.in_duration
THEN (proba3.out_duration / 60) * 0.14
WHEN proba3.out_duration > proba4.in_duration
THEN (proba4.in_duration / 60) * 0.14
+ ((proba3.out_duration - proba4.in_duration)/60) * 0.09
ELSE 0
END AS BAL2
FROM proba2
LEFT JOIN proba ON proba2.p_name = proba.p_name
LEFT JOIN proba1 ON proba1.p_name = proba1.p_name
LEFT JOIN proba3 ON proba3.p_name = proba3.p_name
LEFT JOIN proba4 ON proba4.p_name = proba4.p_name
WHERE
proba.p_name IN ('CZE', 'FRA')
AND proba1.p_name IN ('CZE', 'FRA')
AND proba3.p_name IN ('CZE', 'FRA')
AND proba4.p_name IN ('CZE', 'FRA')
)
GROUP BY proba.p_name;
我认为下面的代码应该完成所有这些视图组合所尝试的工作/希望更容易看到正在发生的事情:
create view probAll as
select coalesce(tin.oper,tout.oper) as p_name
, sum
(
0.14 * tout.duration / 60
+ case
when tout.duration > tin.duration
then 0.09 * (tout.duration - tin.duration) / 60
else 0
end
)
from
(
select oper
, EXTRACT(Year FROM DATE timestamp) as tYear
, EXTRACT(Month FROM DATE timestamp) as tMonth
, sum(duration) as Balance
from TA_OUT
group by oper
, EXTRACT(Year FROM DATE timestamp)
, EXTRACT(Month FROM DATE timestamp)
) as tout
full outer join
(
select oper
, EXTRACT(Year FROM DATE timestamp) as tYear
, EXTRACT(Month FROM DATE timestamp) as tMonth
, sum(duration) as Balance
from TA_IN
group by oper
, EXTRACT(Year FROM DATE timestamp)
, EXTRACT(Month FROM DATE timestamp)
) as tin
on tin.oper = tout.oper
and tin.tyear = tout.tyear
and tin.tmonth = tout.tmonth
where coalesce(tin.oper,tout.oper) in ('CZE','FRA')
and coalesce(tin.tyear,tout.tyear) = 2013
and coalesce(tin.tmonth,tout.tmonth) in (5, 6)
group by coalesce(tin.oper,tout.oper)
未经测试然而,问题是我不能仅按p_名称分组,因为我也应该按持续时间分组。-为什么?看看你的初始视图,你在同一个字段上有distinct和group by——仅供参考:当使用group by时,该值的定义是distinct的。e、 g.如果你有一堆黑白球,你把它们分成两个袋子,你会有两个不同的袋子——一个装着白色球,一个装着黑色球。谢谢你的帮助,也谢谢你对分组方式和不同方式的解释,这真的很有用。上面的脚本给了我一个错误:ORA-00936:missing expression,我认为这是因为字段timestamp it是Varchar2而不是date。您可以将其从string转换为date,为前6个字符yyyymm的字段添加子字符串,也可以按照原始格式使用like语句。就我个人而言,如果您能够的话,我建议将该列的类型转换为日期——假设它总是包含日期;它将在功能和性能上获得回报。非常感谢您的帮助。脚本正在工作,我只是在选择proba.p_name作为p_name之后加上,因为没有这个别名,它会给我错误提示ORA:Invalidindentifire@DejanIvanov你好我正在整理最后的答案。我看这个还没有被接受。你还有什么问题吗?如果它解决了你的问题,不要忘记upvote+accept是最好的奖励;谢谢,祝你今天愉快。
create view probAll as
select coalesce(tin.oper,tout.oper) as p_name
, sum
(
0.14 * tout.duration / 60
+ case
when tout.duration > tin.duration
then 0.09 * (tout.duration - tin.duration) / 60
else 0
end
)
from
(
select oper
, EXTRACT(Year FROM DATE timestamp) as tYear
, EXTRACT(Month FROM DATE timestamp) as tMonth
, sum(duration) as Balance
from TA_OUT
group by oper
, EXTRACT(Year FROM DATE timestamp)
, EXTRACT(Month FROM DATE timestamp)
) as tout
full outer join
(
select oper
, EXTRACT(Year FROM DATE timestamp) as tYear
, EXTRACT(Month FROM DATE timestamp) as tMonth
, sum(duration) as Balance
from TA_IN
group by oper
, EXTRACT(Year FROM DATE timestamp)
, EXTRACT(Month FROM DATE timestamp)
) as tin
on tin.oper = tout.oper
and tin.tyear = tout.tyear
and tin.tmonth = tout.tmonth
where coalesce(tin.oper,tout.oper) in ('CZE','FRA')
and coalesce(tin.tyear,tout.tyear) = 2013
and coalesce(tin.tmonth,tout.tmonth) in (5, 6)
group by coalesce(tin.oper,tout.oper)