Sql 从查询中获取结果

我想写一个查询，这样我就可以像

CREATE TABLE TEMP25
(
  STATUS  VARCHAR2(200 BYTE)
);

Insert into TEMP25
   (STATUS)
 Values
   ('PENDING');
Insert into TEMP25
   (STATUS)
 Values
   ('ERROR');
Insert into TEMP25
   (STATUS)
 Values
  ('ERROR');
Insert into TEMP25
   (STATUS)
 Values
   ('ERROR');
Insert into TEMP25
   (STATUS)
 Values
   ('NOT_REQUIRED');
Insert into TEMP25
   (STATUS)
 Values
   ('NOT_REQUIRED'); 
Insert into TEMP25
   (STATUS)
 Values
   ('PENDING');
Insert into TEMP25
   (STATUS)
 Values
   ('PENDING');
Insert into TEMP25
  (STATUS)
 Values
   ('ERROR');
Insert into TEMP25
   (STATUS)
Values
  ('NOT_REQUIRED');
Insert into TEMP25
  (STATUS)
 Values
  ('ERROR');
Insert into TEMP25
   (STATUS)
 Values
  ('INVALID');
Insert into TEMP25
   (STATUS) 
 Values
   ('INVALID');
Insert into TEMP25
  (STATUS)
 Values
  ('PENDING');

---

我希望记录按顺序排列，在一个查询中，我已尝试使用with table子句它可以工作…是否有其他解决方案…并且不希望出现无效记录

您可以轻松地使用case when语句并获得此结果…也要查看它

TOTAL_RECORDS  TOTAL_PENDING TOTAL_NOT_REQUIRED   TOTAL_PENDING
-----------------------------------------------------------------
   14               4             3                   5 
-----------------------------------------------------------------

---

你可以很容易地使用case-when语句并得到这个结果…也可以查看它

TOTAL_RECORDS  TOTAL_PENDING TOTAL_NOT_REQUIRED   TOTAL_PENDING
-----------------------------------------------------------------
   14               4             3                   5 
-----------------------------------------------------------------

如果愿意，您可以使用SUM/CASE或SUM/DECODE

Select    COUNT(*) TOTAL_RECORDS  ,    
SUM(case when status = 'ERROR' then 1 else 0 END) TOTAL_ERROR   
SUM(case when status = 'NOT_REQUIRED' then 1 else 0 END) TOTAL_NOT_REQUIRED,     
SUM(case when status = 'PENDING' then 1 else 0 END) TOTAL_PENDING,  
FROM temp25

您也可以使用pivot，但获取计数*有点难看

Select
   COUNT(*) TOTAL_RECORDS  ,
   SUM(case when status = 'PENDING' then 1 else 0 END) TOTAL_PENDING, 
   SUM(case when status = 'NOT_REQUIRED' then 1 else 0 END) TOTAL_NOT_REQUIRED, 
   SUM(case when status = 'ERROR' then 1 else 0 END) TOTAL_ERROR


FROM temp25

如果愿意，您可以使用SUM/CASE或SUM/DECODE

Select    COUNT(*) TOTAL_RECORDS  ,    
SUM(case when status = 'ERROR' then 1 else 0 END) TOTAL_ERROR   
SUM(case when status = 'NOT_REQUIRED' then 1 else 0 END) TOTAL_NOT_REQUIRED,     
SUM(case when status = 'PENDING' then 1 else 0 END) TOTAL_PENDING,  
FROM temp25

您也可以使用pivot，但获取计数*有点难看

Select
   COUNT(*) TOTAL_RECORDS  ,
   SUM(case when status = 'PENDING' then 1 else 0 END) TOTAL_PENDING, 
   SUM(case when status = 'NOT_REQUIRED' then 1 else 0 END) TOTAL_NOT_REQUIRED, 
   SUM(case when status = 'ERROR' then 1 else 0 END) TOTAL_ERROR


FROM temp25

在甲骨文中，你可以

WITH 
COUNTS AS(
select * 
from (
   select status
   from TEMP25 t
)
pivot 
(
   count(status)
   for status in ('PENDING' AS TOTAL_PENDING,
                  'NOT_REQUIRED' AS TOTAL_NOT_REQUIRED,
                  'ERROR' AS TOTAL_ERROR)
))


SELECT COUNT(*) total_records, 
       total_pending, 
       total_not_required, 
       total_error 
FROM   temp25, 
       counts 
GROUP  BY total_pending, 
          total_not_required, 
          total_error 

所有数据库都有一个空表，您可以从这种东西中使用。

在Oracle中，您可以

WITH 
COUNTS AS(
select * 
from (
   select status
   from TEMP25 t
)
pivot 
(
   count(status)
   for status in ('PENDING' AS TOTAL_PENDING,
                  'NOT_REQUIRED' AS TOTAL_NOT_REQUIRED,
                  'ERROR' AS TOTAL_ERROR)
))


SELECT COUNT(*) total_records, 
       total_pending, 
       total_not_required, 
       total_error 
FROM   temp25, 
       counts 
GROUP  BY total_pending, 
          total_not_required, 
          total_error 

---

所有数据库都有一个空表，您可以从这类数据中使用。

前面的答案具有对源表进行单次扫描的优势。前面的答案具有对源表进行单次扫描的优势。