Swift 如何处理这个功能?
我想写一个函数,让街头战士交替攻击他们。每一次攻击都会吸引一些人的心。当其中一个战士有0颗心时,战斗就结束了。但我不知道如何一次又一次地做这个过程。这就是我的代码现在的样子:Swift 如何处理这个功能?,swift,function,for-in-loop,Swift,Function,For In Loop,我想写一个函数,让街头战士交替攻击他们。每一次攻击都会吸引一些人的心。当其中一个战士有0颗心时,战斗就结束了。但我不知道如何一次又一次地做这个过程。这就是我的代码现在的样子: public struct StreetFighter { var name: String var power: Int var defence: Int var hearts: Int func Attack() { print("\(name) is
public struct StreetFighter {
var name: String
var power: Int
var defence: Int
var hearts: Int
func Attack() {
print("\(name) is going into the offence...")
}
func Blocking() {
print("\(name) is blocking the attack")
}
}
var connorMcGregor = StreetFighter(name: "Connor McGregor", power: 8, defence: 7, hearts: 100)
var mikeTyson = StreetFighter(name: "Connor McGregor", power: 9, defence: 6, hearts: 100)
var alisterOverreem = StreetFighter(name: "Alister Overreem", power: 7, defence: 10, hearts: 100)
var khabib = StreetFighter(name: "Khabib", power: 9, defence: 8, hearts: 100)
struct Fight {
var location: String
mutating func Round1(firstFighter: StreetFighter,secondFighter: StreetFighter) -> Int {
firstFighter.Attack()
if firstFighter.power < secondFighter.defence {
secondFighter.Blocking()
secondFighter.Attack()
} else {
secondFighter.hearts - firstFighter.power
}
if secondFighter.power < firstFighter.defence {
firstFighter.Blocking()
} else {
firstFighter.hearts - secondFighter.power
}
if firstFighter.hearts == 0 || secondFighter.hearts == 0 {
print("The fight is over!")
}
return firstFighter.hearts
return secondFighter.hearts
}
}
var mma = Fight(location: "New York")
mma.Round1(firstFighter: connorMcGregor, secondFighter: khabib)
public struct StreetFighter{
变量名称:String
无功功率:Int
var防御:Int
变量:Int
func攻击(){
打印(“\(姓名)将进入犯罪…”)
}
func阻塞(){
打印(“\(名称)正在阻止攻击”)
}
}
var connorMcGregor=街头斗士(姓名:“Connor McGregor”,力量:8,防御:7,心脏:100)
var mikeTyson=街头斗士(姓名:“康纳·麦格雷戈”,力量:9,防守:6,红心:100)
var alisterOverreem=街头斗士(名称:“Alister overseem”,力量:7,防御:10,红心:100)
var khabib=街头斗士(名字:“khabib”,力量:9,防御:8,心脏:100)
结构战{
变量位置:字符串
变异func Round1(第一架战斗机:街机战斗机,第二架战斗机:街机战斗机)->Int{
firstFighter.Attack()
如果First Fighter.power
问题是这个过程在第一轮之后就停止了。我尝试了for in或repeat while循环,但没有成功。
有人能帮我吗?首先,您可以尝试将一些功能移动到
街机本身:
public struct StreetFighter {
let name: String
let power: Int
let defence: Int
var hearts = 100 // you can provide a default value
var isAlive: Bool {
hearts > 0
}
func attack() {
print("\(name) is going into the offence...")
}
mutating func defend(attackingPower: Int) {
if power > defence {
hurt(damage: attackingPower)
} else {
block()
}
}
private func block() {
print("\(name) is blocking the attack")
}
private mutating func hurt(damage: Int) {
print("\(name) is hurt")
hearts -= damage
}
}
然后,在Fight
struct中添加一个带有while
循环的函数(您也可以在那里限制回合数):
根据您的目标,您可能希望从外部提取战斗的某些部分。例如,start
函数可以返回一个结果(谁赢了),然后您可以对其进行操作。1。您有2个返回运算符-它在基本级别上是错误的。您只需返回1次。2.为什么你需要归还红心?第二轮?3.你能告诉我该怎么做吗?您是否希望运行1个函数,并且它必须在所有12轮上运行?最后一轮还赢了?哇,太好了,谢谢!我刚刚开始学习如何在大科罗纳锁定代码,所以我是这方面的新手,但这很有趣!:)
struct Fight {
let location: String
var fighter1: StreetFighter
var fighter2: StreetFighter
mutating func start() {
var roundNumber = 0
while !isFinished && roundNumber < 12 {
roundNumber += 1
round()
print("Round \(roundNumber): \(fighter1.name) - \(fighter1.hearts), \(fighter2.name) - \(fighter2.hearts)")
}
print("The fight is over!")
}
private mutating func round() {
fighter1.attack()
fighter2.defend(attackingPower: fighter1.power)
fighter2.attack()
fighter1.defend(attackingPower: fighter2.power)
}
private var isFinished: Bool {
!fighter1.isAlive || !fighter2.isAlive
}
}
let connorMcGregor = StreetFighter(name: "Connor McGregor", power: 8, defence: 7, hearts: 100)
let mikeTyson = StreetFighter(name: "Connor McGregor", power: 9, defence: 6, hearts: 100)
let alisterOverreem = StreetFighter(name: "Alister Overreem", power: 7, defence: 10, hearts: 100)
let khabib = StreetFighter(name: "Khabib", power: 9, defence: 8) // you can use the default `hearts` count
var mma = Fight(location: "New York", fighter1: connorMcGregor, fighter2: khabib)
mma.start()