Windows 使用命令行列出文件的多种模式
在我的工作目录中，我有以检索的年、月、日和小时命名的文件，如下所示：Windows 使用命令行列出文件的多种模式,windows,cmd,Windows,Cmd,在我的工作目录中，我有以检索的年、月、日和小时命名的文件，如下所示： 19980101.00.nc 19980101.03.nc 19980101.06.nc 19980101.09.nc 19980101.12.nc 19980101.15.nc 19980101.18.nc 19980101.21.nc 19980102.00.nc 19980102.03.nc 19980102.06.nc 19980102.09.nc 19980102.12.nc 19980102.15.nc 19980
19980101.00.nc 19980101.03.nc 19980101.06.nc 19980101.09.nc
19980101.12.nc 19980101.15.nc 19980101.18.nc 19980101.21.nc
19980102.00.nc 19980102.03.nc 19980102.06.nc 19980102.09.nc
19980102.12.nc 19980102.15.nc 19980102.18.nc 19980102.21.nc
19980103.00.nc 19980103.03.nc 19980103.06.nc 19980103.09.nc
19980103.12.nc 19980103.15.nc 19980103.18.nc 19980103.21.nc
19980101.15.nc |
19980101.18.nc |
19980101.21.nc _|_ # these are day 01 files
19980102.00.nc |
19980102.03.nc |
19980102.06.nc |
19980102.09.nc |
19980102.12.nc _|_ # these are day 02 files
dir 19980101.*.nc19980101有什么想法吗？这个问题很不清楚，但这里有一个注释过的批处理文件，它会提示用户输入文件日期，如
19980102@echo off
setlocal EnableExtensions EnableDelayedExpansion
rem Prompt user for date string until a number string with exactly 8 digits is entered.
:EnterFileDate
set "FileDate="
set /P "FileDate=Enter date in format YYYYMMDD: "
rem Has the user nothing entered at all?
if not defined FileDate goto EnterFileDate
rem Has the user entered a string not consisting of only digits?
for /F "delims=0123456789" %%I in ("!FileDate!") do goto EnterFileDate
rem Has the user entered a too long string?
if not "%FileDate:~8%" == "" goto EnterFileDate
rem Has the user entered a too short string?
if "%FileDate:~7%" == "" goto EnterFileDate
rem Has the user entered a string not starting with 19 or 20 for century?
if not "%FileDate:~0,2%" == "19" if not "%FileDate:~0,2%" == "20" goto EnterFileDate
rem Don't care of possible other invalid date strings, but
rem check if the entered date string matches any existing file.
if not exist "%FileDate%.??.nc" (
echo/
echo There is no file "%FileDate%.??.nc".
echo/
goto EnterFileDate
)
rem Discard local environment and pass entered file date
rem to previous environment restored by command ENDLOCAL.
endlocal & set "FileDate=%FileDate%"
set "PrevYear=%FileDate:~0,4%"
set "PrevMonth=%FileDate:~4,2%"
rem Get day in month subtracted by 1 with avoiding to get 01 to 09
rem interpreted as octal number by concatenating this two digits
rem of day in month first with 1 for integer number 101 to 132.
set /A PrevDay=1%FileDate:~6,2% - 101
rem Is day in month greater or equal 1, month must not be changed.
if %PrevDay% GEQ 1 goto BuildPrevDate
set /A PrevMonth=1%PrevMonth% - 101
rem Is month less than 1, year must be changed too.
if %PrevMonth% LSS 1 (
set /A PrevYear-=1
set "PrevMonth=12"
set "PrevDay=31"
goto BuildPrevDate
)
rem Determine last day in new month and year.
if %PrevMonth% == 1 set "PrevDay=31" & goto BuildPrevDate
if %PrevMonth% == 3 set "PrevDay=31" & goto BuildPrevDate
if %PrevMonth% == 4 set "PrevDay=30" & goto BuildPrevDate
if %PrevMonth% == 5 set "PrevDay=31" & goto BuildPrevDate
if %PrevMonth% == 6 set "PrevDay=30" & goto BuildPrevDate
if %PrevMonth% == 7 set "PrevDay=31" & goto BuildPrevDate
if %PrevMonth% == 8 set "PrevDay=31" & goto BuildPrevDate
if %PrevMonth% == 9 set "PrevDay=30" & goto BuildPrevDate
if %PrevMonth% == 10 set "PrevDay=31" & goto BuildPrevDate
if %PrevMonth% == 11 set "PrevDay=30" & goto BuildPrevDate
rem Leap year finding for the years 1901 to 2099.
set /A LeapYear=PrevYear %% 4
if %LeapYear% == 0 (
set "PrevDay=29"
) else (
set "PrevDay=28"
)
set "LeapYear="
:BuildPrevDate
if %PrevDay% LSS 10 set "PrevDay=0%PrevDay%"
if %PrevMonth% LSS 10 set "PrevMonth=0%PrevMonth%"
set "PrevDate=%PrevYear%%PrevMonth%%PrevDay%"
set "PrevDay="
set "PrevMonth="
set "PrevYear="
echo/
dir %PrevDate%.15.nc %PrevDate%.18.nc %PrevDate%.21.nc %FileDate%.00.nc %FileDate%.03.nc %FileDate%.06.nc %FileDate%.09.nc %FileDate%.12.nc
set "FileDate="
set "PrevDate="
echo/
pause
dir/？echo/？endlocal/？获取/？goto/？如果/？暂停/？rem/？设置/？setlocal/？
dirdir*