Android EditText用户输入到命令行（回显“此处的用户输入”等）

我需要从用户的EditText数字中获取整数输入，以使其进入命令行，但如果我将cmd行更改为echo 255>，它似乎无法工作。。。它可以工作，但如果我尝试放置用户输入，而不是255，则不会

这是代码

public class main extends Activity  {

EditText value;
int uin;



/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);


    value = (EditText) findViewById(R.id.editText2);

    try {
        Process process = Runtime.getRuntime().exec("su");
    DataOutputStream os = new  DataOutputStream(process.getOutputStream());
     {
       os.writeBytes("mount -o rw,remount -t yaffs2  /dev/block/mtdblock03 /system\n" +
               "exit \n");
       os.flush();
    process.waitFor();
    }

    } catch (IOException e) {
        e.printStackTrace();
    } catch (InterruptedException e) {
        e.printStackTrace();
    }

    //Button OK

    Button bOK = (Button) findViewById(R.id.bOK);
    bOK.setOnClickListener(new View.OnClickListener() {

        public void onClick(View v) {
            // TODO Auto-generated method stub

            uin = Integer.parseInt(value.getText().toString());

            Process process = null;
            try {
                process = Runtime.getRuntime().exec("su");
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            DataOutputStream os = new 

      DataOutputStream(process.getOutputStream());
            try {
                os.writeBytes("chmod 644 sys/class/leds/button-backlight/brightness\n");
                os.writeBytes("echo" +uin+ "> sys/class/leds/button-backlight/brightness\n");
                os.writeBytes("chmod 444 sys/class/leds/button-backlight/brightness\n");
                os.writeBytes("exit\n");
                os.flush();
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }

---

我的第一个猜测是你缺少空间

如果回声255>。。。这很好，但使用+将字符串连接在一起不会添加隐含空格，因此您的代码当前将生成echo255>sys/class。。。如果uin=255。换句话说，尝试：

os.writeBytes("echo " +uin+ " > sys/class/leds/button-backlight/brightness\n");

嗯