Arrays 这里我得到了预期的操作数错误，错误标记为+； #/bin/bash-x echo“输入整数” 读$val 对于（（i=0；i

两个问题：

#!/bin/bash -x

echo "enter an integer "
read $val

for((i=0;i<=2;i++))
do
Numbers[$i]=$val
done
echo ${Number[@]}
if [ $((${Number[0]}+${Number[1]}+${Number[2]})) -eq 0 ]
then
        echo "Sum is Zero"
else
        echo "Sum is not zero"
fi

！/bin/bash-x
echo“输入整数”
read val#read取变量名
因为（（i=0；i
Number
不是
Number
@oguz，
$（…）
在
[…]
的内部，所以这应该是算术上下文，不是吗？@Paul哦，是的，我的错，我没有注意
#!/bin/bash -x

echo "enter an integer "
read val  # read takes the name of a variable

for((i=0;i<=2;i++))
do
Numbers[$i]=$val
done
echo ${Numbers[@]}  # from here on, you wrote "Number" instead of "Numbers"
if [ $((Numbers[0] + Numbers[1] + Numbers[2])) -eq 0 ]  # you don't need $ to read variables in arithmetic expansions
then
        echo "Sum is Zero"
else
        echo "Sum is not zero"
fi