Arrays 将2个范围合并为一个数组并进行筛选

我有两个范围，都有相同的行数，不同的列数（可以不同）

范围1：

A,   1,   1,   1
B,   2,   4,   8
C,   3,   9,  27
D,   4,  16,  64

范围2：

1,       1
16,     64   
81,    
256,   1024

我想将这些值导入Excel中的多数组，但前提是范围2的第n列（本例中为第2列）不是空值。最后我会有一个数组，看起来像这样：

产出1：

A,   1,   1,   1,    1,     1
B,   2,   4,   8,   16,    32   
D,   4,  16,  64,  256,  1024

到目前为止，我已经启动了一个功能：

Function Report(rng1 As Range, rng2 As Range)
Dim matrix() As Double
Dim all_rng As Range
    all_rng = Union(rng1, rng2)

End Function

---

这是可能的决定。
注：
1.为了测试方便，我将

函数

更改为

Sub

，因为我无法一步一步地完成函数
2.有几行用于测试（在注释中标记）
3.我假设要填充的列的正确数量在其第一行

rng2

中
4.有带有

的注释行。选择
语句-取消注释，用F8一步一步走，您将看到它是如何工作的

答案是

我对你的矩阵是这样的：


并且从第10行开始有这样的输出：


代码如下：

Sub Report() 'rng1 As Range, rng2 As Range)
Dim matrix() As Variant ' use variant if you have a mix of letters and numbers
Dim x As Long, y As Long
Dim r As Long, c As Long
Dim rows() As Long, i As Long, rowCnt As Long


' used for test purposes
Dim rng1 As Range, rng2 As Range
Set rng1 = Range(Cells(1, 1), Cells(4, 4))
Set rng2 = Range(Cells(1, 9), Cells(4, 10))


' find out columns count per each range's row 1
x = Range(rng1.Cells(1, 1), rng1.Cells(1, rng1.Columns.Count)).Columns.Count

' I assume that the correct number of columns in rng2 is in the first row
' you may change the row number if needed
y = Range(rng2.Cells(1, 1), rng2.Cells(1, rng2.Columns.Count)).Columns.Count

' check that all rows have all columns filled
For i = 0 To rng1.rows.Count - 1
    ' if all columns in rng2 are filled then add number of the row to an array of row numbers
    If Not rng2.Cells(i + 1, y) = "    " Then ' fix evaluation condition if needed - that is what was copied from post
        ReDim Preserve rows(rowCnt)
        rows(rowCnt) = i + 1
        rowCnt = rowCnt + 1
    End If
Next

i = UBound(rows) - 1

' set dimension of an matrix array
ReDim matrix(rows(i), x + y)

' start filling the matrix

' go through matrix by row
For r = LBound(rows) To UBound(rows)
        ' fill each row column by column

        'gothrough first range - it has x columns in it
        For c = 0 To x - 1
'        rng1.Cells(rows(r), c + 1).Select
            matrix(r, c) = rng1.Cells(rows(r), c + 1).Value
        Next

        ' then without changing matrix's row
        ' go through second range - it has y columns
        For c = 0 To y - 1
'        rng2.Cells(rows(r), c + 1).Select
            matrix(r, c + rows(UBound(rows))) = rng2.Cells(rows(r), c + 1).Value
        Next
Next

' print the matrix to the sheet (optional - delete when convert this back to Function)
For r = LBound(matrix) To UBound(matrix)
    For c = 0 To x + y - 1
        Cells(10 + r, c + 1) = matrix(r, c)
    Next
Next
End Sub

如果您有任何问题，请发表评论。
阵列备选方案

为了演示一种结构清晰的方法，使用数组而不是在每个单元格中循环：

将数据分配给数组
1
和
2
将第二个数组的列值添加到重新标注尺寸的数组中
通过删除空行（检查数组中的第n列
two
）-通过单个代码行（使用helper函数）重新构造生成的数组
将结果写入任何目标范围-通过单个代码行
辅助函数
getRowNo（）

Function getRowNo(arr) As Variant()
' Note: receives last column values of array two as 1-dim 1based array
' Purp: returns 2-dim 1-based array with non-empty row numbers of array two
    Dim i As Long, ii As Long, tmp()
    ReDim tmp(1 To 1, 1 To UBound(arr))     ' provide for temporary array
    For i = LBound(arr) To UBound(arr)
        If Len(arr(i) & "") Then            ' omit empty item
            ii = ii + 1                     ' increment temp counter
            tmp(1, ii) = i                  ' enter row number of original column data
        End If
    Next i
    ReDim Preserve tmp(1 To 1, 1 To ii)     ' correct last dimension
    getRowno = Application.Transpose(tmp)   ' return 2-dim array with rownumbers to be preserved
End Function

您想要一个二维值数组还是一个包含其他一维值数组的一维数组？一个二维数组，其第二个值范围刚刚附加到结束列。您只需使用x=rng1.columns.count和y=rng2.columns.count，不需要假设。抱歉-我确实有一个问题-当我将其转换为函数时，我在
ReDim Preserve rows（rowCnt）
什么类型的错误？（回家后会回答）抱歉-我修复了那个错误-这是由于我的
Dim
出错造成的。我还没有宣布。现在一切都正常了-你的代码太棒了，谢谢。你是我今天遇到的世界上最好的人：D
Function getRowNo(arr) As Variant()
' Note: receives last column values of array two as 1-dim 1based array
' Purp: returns 2-dim 1-based array with non-empty row numbers of array two
    Dim i As Long, ii As Long, tmp()
    ReDim tmp(1 To 1, 1 To UBound(arr))     ' provide for temporary array
    For i = LBound(arr) To UBound(arr)
        If Len(arr(i) & "") Then            ' omit empty item
            ii = ii + 1                     ' increment temp counter
            tmp(1, ii) = i                  ' enter row number of original column data
        End If
    Next i
    ReDim Preserve tmp(1 To 1, 1 To ii)     ' correct last dimension
    getRowno = Application.Transpose(tmp)   ' return 2-dim array with rownumbers to be preserved
End Function