C “mov”的内存引用过多

C “mov”的内存引用过多,c,assembly,x86,mov,C,Assembly,X86,Mov,我已经看过了所有关于如何解决这个问题的建议线索,但我找不到一条与我的错误相匹配的线索 当我编译时,我得到了太多的“mov”的内存引用,即使我把它们全部去掉 __asm__( "mov 0x8(%ebp), %edx;" "mov 0x8(%edx), %edx;" "cmp $0x0, %edx;" "je notFound;" "sub $0x10, %esp;" "mo

我已经看过了所有关于如何解决这个问题的建议线索,但我找不到一条与我的错误相匹配的线索

当我编译时,我得到了太多的“mov”的内存引用,即使我把它们全部去掉

__asm__(
    "mov    0x8(%ebp),  %edx;"
    "mov    0x8(%edx),  %edx;"
    "cmp        $0x0,       %edx;"
    "je     notFound;"

    "sub        $0x10,      %esp;"
    "movl   0xc(%ebp),  (%esp);"
    "movl   $0x24,      0x8(%esp);"


    "mainloop: "
    "movl   %edx,       0x4(%esp);"
    "call _memcmp;"
    "cmp        $0xffffffff,    %eax;"
    "je     leftBranch;"

    "cmp        $0x1,       %eax;"
    "je     rightBranch;"
    "jne        found;"


    "leftBranch: "
    "mov    0xc(%edx),  %edx;"
    "cmp        $0x0,       %edx;"
    "je     notFound;"
    "jne        mainloop;"

    "rightBranch: "
    "mov    0x10(%edx), %edx;"
    "cmp        $0x0,       %edx;"
    "je     notFound;"
    "jne        mainloop;"

    "notFound: "
    "mov    $0x0,       %eax;"
    "add        $0x10,      %esp;"  
    "leave;"
    "ret;"

    "found: "
    "add        $0x10,      %esp;"
    "leave;"
    "ret;"
);

问题可能出在这一行:

"movl   0xc(%ebp),  (%esp);"
不能在一条mov指令中引用两个内存位置