用c替换文本中的2行而不是1行

我有一个搜索单词“Applicat”并替换整行的代码。现在我正试图让它搜索并替换两行，而不是一行，但我有一个小问题。下面是一个示例文本文件：

姓名：1234

应用：ft_链接

日期：今天

我希望脚本能够将文本文件更改为：

姓名：5678

申请者：无

日期：明天

到目前为止，我的代码工作，但它会重复应用程序行不止一次。。。我做错了什么？提前谢谢

这是我的密码：

FILE *input = fopen(buffer1, "r");       /* open file to read */
FILE *output = fopen("temp.txt", "w");

char buffer[512];
while (fgets(buffer, sizeof(buffer), input) != NULL)
    {

static const char text_to_find[] = "Applicat:";     /* String to search for */

static const char text_to_replace[] = "Applicat: None\n";   /* Replacement string */


static const char text_to_find2[] = "Name";     /* String to search for */

static const char text_to_replace2[] = "Name: 5678\n";  /* Replacement string */


char *pos = strstr(buffer, text_to_find);
if (pos != NULL)
{
fputs(text_to_replace, output);

}

char *pos2 = strstr(buffer, text_to_find2);
if (pos2 != NULL)
{
fputs(text_to_replace2, output);

}
else
fputs(buffer, output);




    }

改变

为此：

char *pos = strstr(buffer, text_to_find);
if (pos != NULL)
{
fputs(text_to_replace, output);

}

char *pos2 = strstr(buffer, text_to_find2);
if (pos2 != NULL)
{
fputs(text_to_replace2, output);

}

if(pos==NULL && pos2==NULL)
   fputs(buffer, output);

或者如果你更喜欢

char *pos = strstr(buffer, text_to_find);
char *pos2 = strstr(buffer, text_to_find2);

if(pos==NULL && pos2==NULL)
   fputs(buffer, output);

if (pos2 != NULL)
    fputs(text_to_replace2, output);

if (pos != NULL)
    fputs(text_to_replace, output);

---

您刚刚错过了一个

其他
：

char *pos = strstr(buffer, text_to_find);
char *pos2 = strstr(buffer, text_to_find2);
if (pos != NULL) {
    fputs(text_to_replace, output);
} else if (pos2 != NULL) {
    fputs(text_to_replace2, output);
} else
    fputs(buffer, output);

char *pos = strstr(buffer, text_to_find);
char *pos2 = strstr(buffer, text_to_find2);
if (pos != NULL) {
    fputs(text_to_replace, output);
} else if (pos2 != NULL) {
    fputs(text_to_replace2, output);
} else
    fputs(buffer, output);