输入/输出XORD字符串的C++问题 我是C++初学者，我正在做一个XOR加密程序。当我手动将代码输入到我的程序中时，我的程序运行良好。当我试图解密一个加密的短语，而程序只返回该短语的第一个单词时，就会出现这个问题

例如： 要加密的输入字符串：hello world

关键词：q

加密字符串：V

输入要解密的字符串：V

关键词：q

输出：您好

它只给了我第一个单词，我想这与我获取输入和输出的方式有关

非常感谢你

#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <string>
#include <fstream>

using namespace std;
/*Encrypt/decrypt program that takes in a string and encrypts it using a single byte xor encryption. Program can also decrypt a given string with or without a key.*/

string XOR(string input, char key){
    string XORString = input;
    string newXOR = "";
    for(int i = 0; i < input.length();i++){
       newXOR += XORString[i]^(int(key+i))%255;
    }
    return newXOR;
}

int main()
{
    /*char key = 'q';
    std::cout << XOR("hello world",key);
    return 0;
   The lines above are for manual testing if needed*/
    bool b = true;
    while(b){
        int x;
        cout<<"Enter 1 for Encryption, 2 for Decryption, 3 for Decryption without key or 4 to end program."<<endl;
        cin>>x;
        if(x==1){
            string phrase1 = "";
            cout<< "Enter a phrase to encrypt: ";
            cin.ignore();
            getline(std::cin,phrase1);
            cout<<"Enter a key to encrypt with: ";
            char key1;
            cin>> key1;
            std::cout << XOR(phrase1,key1)<< endl;
       }
        else if(x==2){
            string phrase = "";
            cout<< "Enter a phrase to decrypt: ";
            cin.ignore();
            std::getline(std::cin,phrase);
            cout<<"Enter a key to decrypt with: ";
            char key2;
            cin>>key2;
            std::cout << XOR(phrase,key2)<<endl;
        }
        else if(x==3){
            char keys [] = {'!','"','#','$','%','&','(',')','*','+',',','-','.','/','0','1','2','3','4','5','6','7','8','9',':',';','<','=','>','?','@','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z','[',']','^','_','`','a','b','c','d','e','f','g','h','I','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','{','|','}','~'};
            int end = 92;
            int count = 0;
            string s;
            cout<< "Enter phrase: ";
            cin>>s;
            for(int i = 0; i < 92;i++){
                count++;
                cout<<count<<" possible combination out of " << end << " using " << keys[i]<< ":"<<XOR(s,keys[i])<<endl;
            }
        }
        else if(x==4){
            cout<<"Have a nice day!";
            b = false;
        }
        else{
            cout<<"You entered an invalid number";
            break;
        }
    }
    return 0;

这可能是问题代码：

            string phrase1 = "";
            cout<< "Enter a phrase to encrypt: ";
            cin.ignore();
            getline(std::cin,phrase1);

---

我认为问题在于字符串XORString函数，请尝试以下方法：

//change this
newXOR += XORString[i]^(int(key+i))%255;
//to
newXOR = XORString[i];

---

我希望这能解决我对运算符exclusive OR不太了解的问题，但我认为这是导致字符串函数出现问题的原因

如果它不起作用，请告诉我，以便我可以尝试找到另一种解决方法。^的优先级是否高于%？添加括号可以为你自己和你的读者省去很多痛苦。这可能是一个字符异或的问题。如果字符相等，您将生成一个空字符，即C/C++中表示字符串结尾的控制字符。XOR表示二进制；您应该重新处理或编码生成的二进制文件，或者使用另一种加密方案，如模块相加