C++ C+中的指针和引用有问题+；

我试图调用一个函数，该函数将更改对变量的引用，但每次运行该程序时，我都会得到一个错误的访问

#include <iostream>
#include <fstream>
#include "calculations.hpp"

using namespace std;

int main(int argc, const char * argv[]) {
    char input[12];
    string input2;
    string nameOfFood;
    int *numberOfServings = 0;// THIS IS WHERE I KEEP GETTING THE BAD    ACCESS
    int *calories = 0;
    float *fatInGrams = 0;
    float *carbsInGrams = 0;
    float *fiberInGrams = 0;
    float *proteinInGrams = 0;
    int count = 0;
//    Open an output file
    ofstream outData; //IGNORE
//    Start a loop

    for(int i = 0; i<5; i++){
        //    On the console, ask if the user ate. If the answer is No, be creative, but polite in your answer.
        cout << "did you eat? yes or no" << endl;
        cin >> input;
        if (input[0] == 'y'){
            cout << "Please enter the name; number of servings; calories; amount of fat";
            cout << "; number of carbs; amount of fiber; and the amount of protein" << endl;
            cin >> nameOfFood
            >> *numberOfServings
            >> *calories
            >> *fatInGrams
            >> *carbsInGrams
            >> *fiberInGrams
            >> *proteinInGrams;
            calculate(nameOfFood, numberOfServings, calories, fatInGrams,carbsInGrams, fiberInGrams, proteinInGrams);
            i = 0;
            count++;

        }
        if (input[0] == 'n'){
            i = 5;
        }
    }
    cout << count << endl;
    cout << "calories is " << &calories << endl;
    cout << "number of servings is " << &numberOfServings << endl;

#包括
#包括
#包括“计算.hpp”
使用名称空间std；
int main（int argc，const char*argv[]{
字符输入[12]；
字符串输入2；
食物的名称；
int*numberOfServings=0；//这就是我不断获得错误访问的地方
int*卡路里=0；
浮点数*fatInGrams=0；
浮球*carbsInGrams=0；
浮点*光纤图=0；
浮点数*保护图=0；
整数计数=0；
//打开输出文件
ofstream outData；//忽略
//开始循环
对于（int i=0；i*numberOfServings）
>>*卡路里
>>*法丁格拉姆斯
>>*卡宾卡
>>*纤维图像
>>*蛋白质图谱；
计算（食物名称、份数、卡路里、脂肪、碳水化合物、纤维、蛋白质）；
i=0；
计数++；
}
如果（输入[0]=“n”）{
i=5；
}
}
cout您应该传递有效变量的地址以进行计算

string nameOfFood;
int   numberOfServings = 0;
int   calories = 0;
float fatInGrams = 0;
float carbsInGrams = 0;
float fiberInGrams = 0;
float proteinInGrams = 0;

calculate(nameOfFood, &numberOfServings, &calories, &fatInGrams, &carbsInGrams, &fiberInGrams, &proteinInGrams);
                      ^Address of numberOfServings

在计算函数中

calculate(string nameOfFood, int* numberOfServings, int* calories, float* fatInGrams, float* carbsInGrams, float* fiberInGrams, float* proteinInGrams)
 {
     // Inside the function.
     // numberOfServings is a pointer to the variable.

     // Thus *numberOfServings dereference the pointer and
     // allows you to assign the variable that it points at.

     *numberOfServings = 24; // modifies the variable that was pointed at.

初始化变量时，如：

int *numberOfServings = 0;

它不指向任何内容。取消引用此类指针会导致未定义的行为。因此，行：

    cin ....
        >> *numberOfServings 

这是错误的

最简单的修复方法是将变量
numberOfServings
声明为
int
类型的对象，而不是指针

int numberOfServings = 0;

然后将其读入的位置更改为：

    cin ....
        >> numberOfServings // Drop the *

对其进行类似的修复

int *calories = 0;
float *fatInGrams = 0;
float *carbsInGrams = 0;
float *fiberInGrams = 0;
float *proteinInGrams = 0;

停止使用指针。从代码中删除所有指针。好了，就是这样。：）好的，那么当我在计算函数中时，它是如何工作的？
    cin ....
        >> numberOfServings // Drop the *

int *calories = 0;
float *fatInGrams = 0;
float *carbsInGrams = 0;
float *fiberInGrams = 0;
float *proteinInGrams = 0;