我如何组合多个动作<;T>;变成一个动作<;T>;在C#中?
如何在循环中构建动作?解释(抱歉,太长了) 我有以下资料:我如何组合多个动作<;T>;变成一个动作<;T>;在C#中?,c#,lambda,C#,Lambda,如何在循环中构建动作?解释(抱歉,太长了) 我有以下资料: public interface ISomeInterface { void MethodOne(); void MethodTwo(string folder); } public class SomeFinder : ISomeInterface { // elided } 以及使用上述内容的类: public Map Builder.BuildMap(Action<ISomeInterface>
public interface ISomeInterface {
void MethodOne();
void MethodTwo(string folder);
}
public class SomeFinder : ISomeInterface
{ // elided
}
以及使用上述内容的类:
public Map Builder.BuildMap(Action<ISomeInterface> action,
string usedByISomeInterfaceMethods)
{
var finder = new SomeFinder();
action(finder);
}
如何以编程方式构建第二个实现?i、 e
List<string> folders = new { "folder1", "folder2", "folder3" };
folders.ForEach(folder =>
{
/* do something here to add current folder to an expression
so that at the end I end up with a single object that would
look like:
builder.BuildMap(z => {
z.MethodTwo("folder1");
z.MethodTwo("folder2");
z.MethodTwo("folder3");
}, "IYetAnotherInterfaceName");
*/
});
List folders=new{“folder1”、“folder2”、“folder3”};
folders.ForEach(folder=>
{
/*在此处执行某些操作以将当前文件夹添加到表达式
最后我得到了一个单独的物体
看起来像:
BuildMap(z=>{
z、 方法二(“folder1”);
z、 方法二(“folder2”);
z、 方法二(“folder3”);
},“IYetAnotherInterfaceName”);
*/
});
我一直在想我需要一个
Expression<Action<ISomeInterface>> x
表达式x
或者类似的东西,但对于我来说,我不知道如何构建我想要的东西。任何想法都将不胜感激 这真的很容易,因为代理已经是多播的:
Action<ISomeInterface> action1 = z => z.MethodOne();
Action<ISomeInterface> action2 = z => z.MethodTwo("relativeFolderName");
builder.BuildMap(action1 + action2, "IAnotherInterfaceName");
Action action1=z=>z.MethodOne();
Action action2=z=>z.MethodTwo(“relativeFolderName”);
BuildMap(action1+action2,“iOnotherInterfaceName”);
或者,如果你因为某种原因收集了一批:
IEnumerable<Action<ISomeInterface>> actions = GetActions();
Action<ISomeInterface> action = null;
foreach (Action<ISomeInterface> singleAction in actions)
{
action += singleAction;
}
IEnumerable actions=GetActions();
Action=null;
foreach(动作中的单动作)
{
动作+=单动作;
}
甚至:
IEnumerable<Action<ISomeInterface>> actions = GetActions();
Action<ISomeInterface> action = (Action<ISomeInterface>)
Delegate.Combine(actions.ToArray());
IEnumerable actions=GetActions();
动作动作=(动作)
Delegate.Combine(actions.ToArray());
感谢您的快速响应!我现在正在尝试这个,但到目前为止它看起来不错。这就成功了,谢谢!这是一个很好的提醒,首先要考虑简单的解决方案!这太美了。直到刚才我才真正理解多播代理的作用。
IEnumerable<Action<ISomeInterface>> actions = GetActions();
Action<ISomeInterface> action = (Action<ISomeInterface>)
Delegate.Combine(actions.ToArray());