C# 如何使用а；使用xamarin从SQLite自动分配ID

我有一个输入ID的字段和一个行读取按钮。 当您写入ID并单击按钮时，会出现一条消息，其中相应的行上有信息。 我想删除按钮“Read”和输入字段，这样当用户单击相应的行时，将显示一条包含该行信息的消息

我的xaml.cs代码是：

async void ReadCity()
    {
        if (!string.IsNullOrEmpty(txtPersonId.Text))
        {
            //Get Person
            var person = await App.SQLiteDb.GetItemAsync(Convert.ToInt32(txtPersonId.Text));
            if (person != null)
            {
               
                await DisplayAlert("Success", "Person Name: " + person.Name, "OK");
            }
        }
        else
        {
            await DisplayAlert("Required", "Please Enter PersonID", "OK");
        }
    }

    void BtnRead_Clicked(System.Object sender, System.EventArgs e)
    {
        ReadCity();
    }

我的xaml代码是：

            <StackLayout HorizontalOptions="Center" VerticalOptions="Start">
            <Label Margin="0,0,0,10" Text="FAVORITES" FontAttributes="Bold" FontSize="Large" TextColor="Gray" HorizontalTextAlignment="Center" ></Label>
            <Entry x:Name="txtPersonId" Placeholder="City ID for Delete"></Entry>
            <StackLayout HorizontalOptions="CenterAndExpand" Orientation="Horizontal">
            <Button x:Name="btnDelete" WidthRequest="200" Text="Delete" Clicked="BtnDelete_Clicked" />
                <Button x:Name="btnRead" WidthRequest="200" Text="Read" Clicked="BtnRead_Clicked" />
            </StackLayout>
            <ListView x:Name="lstPersons">
                <ListView.ItemTemplate>
                    <DataTemplate>
                        <TextCell Text="{Binding Name}" Detail="{Binding PersonID}"></TextCell>
                    </DataTemplate>
                </ListView.ItemTemplate>
            </ListView>
            </StackLayout>

是否有办法删除读取按钮并获取与按下行相关的ID？

使用ListView“SelectionChanged”事件：

使用ListView“SelectionChanged”事件：

---

当用户点击一个项目时，将触发两个事件，“ItemTapped”和“ItemSelected”。它们之间的区别在于，“ItemSelected”仅在选择更改时才会触发。如果您想单击项目以显示项目信息，“ItemTapped”是一个更好的选择

XAML：

---

当用户点击一个项目时，将触发两个事件，“ItemTapped”和“ItemSelected”。它们之间的区别在于，“ItemSelected”仅在选择更改时才会触发。如果您想单击项目以显示项目信息，“ItemTapped”是一个更好的选择

XAML：

<ListView SelectionMode="Single"
    ItemsSource="{Binding PersonCollection}"
    SelectedItem="{Binding SelectedPerson}"
    SelectionChanged="ListView_SelectionChanged">

        private void ListView_SelectionChanged(object sender, SelectionChangedEventArgs e)
        {
            if (e.CurrentSelection.Count != 0)
            {
                var bc = this.BindingContext as  YourViewModelName;
                // now you have bc.SelectedPerson and you can access it's properties
                // Display what ever you want 
                collection.SelectedItem = null; // if you want to clear selection
            }
        }

<ListView ItemsSource="{Binding People}"
          SelectionMode="Single"
          ItemSelected="ListView_ItemSelected"
          ItemTapped="ListView_ItemTapped">

private async void ListView_ItemTapped(object sender, ItemTappedEventArgs e)
{
    await DisplayAlert("Tapped", "Person Name: " + (e.Item as Person).Name, "OK");
}

private async void ListView_ItemSelected(object sender, SelectedItemChangedEventArgs e)
{
    await DisplayAlert("Selected", "Person Name: " + (e.SelectedItem as Person).Name, "OK");
}