Grails 使用Kerberos的域身份验证失败

我的应用程序使用Grails、Spring和Kerberos

applicationContext.xml

据我所知，Kerberos域身份验证是成功的。但我在网页上看到：

java.lang.NullPointerException
at org.springframework.security.kerberos.authentication.sun.SunJaasKerberosTicketValidator$KerberosValidateAction.run(SunJaasKerberosTicketValidator.java:162)
at org.springframework.security.kerberos.authentication.sun.SunJaasKerberosTicketValidator$KerberosValidateAction.run(SunJaasKerberosTicketValidator.java:151)
at java.security.AccessController.doPrivileged(Native Method)
at javax.security.auth.Subject.doAs(Subject.java:422)
at org.springframework.security.kerberos.authentication.sun.SunJaasKerberosTicketValidator.validateTicket(SunJaasKerberosTicketValidator.java:66)
at org.springframework.security.kerberos.authentication.KerberosServiceAuthenticationProvider.authenticate(KerberosServiceAuthenticationProvider.java:64)
at org.springframework.security.authentication.ProviderManager.authenticate(ProviderManager.java:156)
....

NPE以直线形式出现

String user = context.getSrcName().toString();

因为context.getSrcName==null。怎么了

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注：还有一刻：当我输入错误的密码时，它会再次要求我输入密码。

我找到了解决方案：刚刚将jdk1.8更改为jdk1.7。

对我来说，这不是一个选项，不幸的是，我也遇到了同样的错误。

java.lang.NullPointerException
at org.springframework.security.kerberos.authentication.sun.SunJaasKerberosTicketValidator$KerberosValidateAction.run(SunJaasKerberosTicketValidator.java:162)
at org.springframework.security.kerberos.authentication.sun.SunJaasKerberosTicketValidator$KerberosValidateAction.run(SunJaasKerberosTicketValidator.java:151)
at java.security.AccessController.doPrivileged(Native Method)
at javax.security.auth.Subject.doAs(Subject.java:422)
at org.springframework.security.kerberos.authentication.sun.SunJaasKerberosTicketValidator.validateTicket(SunJaasKerberosTicketValidator.java:66)
at org.springframework.security.kerberos.authentication.KerberosServiceAuthenticationProvider.authenticate(KerberosServiceAuthenticationProvider.java:64)
at org.springframework.security.authentication.ProviderManager.authenticate(ProviderManager.java:156)
....

String user = context.getSrcName().toString();