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Ios 从Objective-C中的JSON API获取一个值

ios objective-c json

Ios 从Objective-C中的JSON API获取一个值,ios,objective-c,json,Ios,Objective C,Json,我试图从JSON中获取一个值。JSON位于NSString中，如下所示： {"coord":{"lon":-122.38,"lat":37.57},"weather":[{"id":300,"main":"Drizzle","description":"Lekka m≈ºawka","icon":"09d"}],"base":"stations","main":{"temp":304.74,"pressure":1017,"humidity":35,"temp_min":300.15,"temp

我试图从JSON中获取一个值。JSON位于NSString中，如下所示：

{"coord":{"lon":-122.38,"lat":37.57},"weather":[{"id":300,"main":"Drizzle","description":"Lekka mżawka","icon":"09d"}],"base":"stations","main":{"temp":304.74,"pressure":1017,"humidity":35,"temp_min":300.15,"temp_max":307.59},"visibility":16093,"wind":{"speed":6.7,"deg":250},"clouds":{"all":75},"dt":1437346641,"sys":{"type":1,"id":478,"message":0.0615,"country":"US","sunrise":1437311022,"sunset":1437362859},"id":5357155,"name":"Hillsborough","cod":200}
我对“临时工”很感兴趣。我应该怎么做？

假设您的JSON字符串存储为名为JSONString的NSString：

    NSError *error;
    NSDictionary *keys = [NSJSONSerialization JSONObjectWithData:[JSONString dataUsingEncoding:NSUTF8StringEncoding]
                                                         options:NSJSONReadingMutableContainers
                                                           error:&error];
    NSLog(@"temp = %@", keys[@"main"][@"temp"]); // temp = 304.74
要获取weather中的主要子项，即包含多个项的数组，您应该指出其索引，以告诉选择器数组中的哪个对象是您要查找的对象。在本例中，它是
0
：

NSLog(@"weather = %@", keys[@"weather"][0][@"main"]); // weather = Drizzle
很好，谢谢。如果我能再问一个问题：从“天气”（例如细雨）中获取“主要”是什么？我试图使它类似于温度，但应用程序崩溃了。前面有额外的“[”号。