Iphone 使用Oauth2成功进行身份验证后获取用户信息

Iphone 使用Oauth2成功进行身份验证后获取用户信息,iphone,ios,oauth-2.0,google-oauth,Iphone,Ios,Oauth 2.0,Google Oauth,在我的iPhone应用程序中,我正在使用google登录,使用的是Oauth2,我正在跟踪并成功登录 - (void)viewController:(GTMOAuth2ViewControllerTouch * )viewController finishedWithAuth:(GTMOAuth2Authentication * )auth error:(NSError * )error { if(!error) { UIAler

在我的iPhone应用程序中,我正在使用google登录,使用的是
Oauth2
,我正在跟踪并成功登录

- (void)viewController:(GTMOAuth2ViewControllerTouch * )viewController
      finishedWithAuth:(GTMOAuth2Authentication * )auth
                 error:(NSError * )error
{


if(!error)
    {
    UIAlertView * alert = [[UIAlertView alloc] initWithTitle:@"Success Authorizing with Google"

                                                         message:nil
                                                        delegate:nil
                                               cancelButtonTitle:@"OK"
                                               otherButtonTitles:nil];
        [alert show];
    }
我正在使用范围进行
GTMOAuth2Authentication
,现在我想获得用户的基本信息,如姓名、年龄、电子邮件等

那么,我如何才能获得所有细节??
我找了很多东西,但什么也没找到

可能是重复的问题,但也没有帮助

请提供帮助默认情况下,GTMOAuth2ViewControllerTouch viewController将获取用户的电子邮件,但不会获取用户配置文件的其余部分。
通过在登录前设置此属性,可以从谷歌服务器请求完整配置文件:

GTMOAuth2ViewControllerTouch*viewController
viewController.signIn.shouldFetchGoogleUserProfile=YES

以身份登录后,配置文件将可用

要获取其他信息,您必须更改
范围
字符串并再次开始获取

下面是一些作用域URL

@”https://www.googleapis.com/auth/plus.me“

@”https://www.googleapis.com/auth/userinfo.email“

@”https://www.googleapis.com/auth/tasks“

默认情况下,GTMOAuth2ViewControllerTouch viewController将获取用户的电子邮件,但不会获取用户配置文件的其余部分。
通过在登录前设置此属性,可以从谷歌服务器请求完整配置文件:

GTMOAuth2ViewControllerTouch*viewController
viewController.signIn.shouldFetchGoogleUserProfile=YES

以身份登录后,配置文件将可用

要获取其他信息,您必须更改
范围
字符串并再次开始获取

下面是一些作用域URL

@”https://www.googleapis.com/auth/plus.me“

@”https://www.googleapis.com/auth/userinfo.email“


@”https://www.googleapis.com/auth/tasks“

使用此代码解决了此问题

 NSURL *url = [NSURL URLWithString:@"https://www.googleapis.com/plus/v1/people/me/activities/public"];
            NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
            [self.auth authorizeRequest:request
                      completionHandler:^(NSError *error) {
                          NSString *output = nil;
                          if (error) {
                              output = [error description];
                          } else {
                              // Synchronous fetches like this are a really bad idea in Cocoa applications
                              //
                              // For a very easy async alternative, we could use GTMHTTPFetcher
                              NSURLResponse *response = nil;
                              NSData *data = [NSURLConnection sendSynchronousRequest:request
                                                                   returningResponse:&response
                                                                               error:&error];
                              if (data) {
                                  // API fetch succeeded
                                  output = [[NSString alloc] initWithData:data
                                                                 encoding:NSUTF8StringEncoding] ;

                                  NSError* error;
                                  NSDictionary* json = [NSJSONSerialization
                                                        JSONObjectWithData:data

                                                        options:kNilOptions
                                                        error:&error];



                                  NSArray *array=[json objectForKey:@"items"];
                                  if (array.count>0) {
                                      NSDictionary *dicts=[array objectAtIndex:0];

                                      //  NSLog(@"actor:%@",[dicts objectForKey:@"actor"]);
                                      //[self updateUI:[dicts objectForKey:@"actor"]];
                                      // [dictUserInfo setObject:[[[dicts objectForKey:@"actor"] objectForKey:@"image"]objectForKey:@"url"] forKey:@"imageUrl"];


                                      if([delegate respondsToSelector:@selector(userPicChanged:)])
                                      {
                                          //send the delegate function with the amount entered by the user
                                          [delegate userPicChanged:[[[dicts objectForKey:@"actor"] objectForKey:@"image"]objectForKey:@"url"]];
                                      }



                                  }


                              } else {
                                  // fetch failed
                                  output = [error description];
                              }
                          }
                      }];

用这个代码解决了它

 NSURL *url = [NSURL URLWithString:@"https://www.googleapis.com/plus/v1/people/me/activities/public"];
            NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
            [self.auth authorizeRequest:request
                      completionHandler:^(NSError *error) {
                          NSString *output = nil;
                          if (error) {
                              output = [error description];
                          } else {
                              // Synchronous fetches like this are a really bad idea in Cocoa applications
                              //
                              // For a very easy async alternative, we could use GTMHTTPFetcher
                              NSURLResponse *response = nil;
                              NSData *data = [NSURLConnection sendSynchronousRequest:request
                                                                   returningResponse:&response
                                                                               error:&error];
                              if (data) {
                                  // API fetch succeeded
                                  output = [[NSString alloc] initWithData:data
                                                                 encoding:NSUTF8StringEncoding] ;

                                  NSError* error;
                                  NSDictionary* json = [NSJSONSerialization
                                                        JSONObjectWithData:data

                                                        options:kNilOptions
                                                        error:&error];



                                  NSArray *array=[json objectForKey:@"items"];
                                  if (array.count>0) {
                                      NSDictionary *dicts=[array objectAtIndex:0];

                                      //  NSLog(@"actor:%@",[dicts objectForKey:@"actor"]);
                                      //[self updateUI:[dicts objectForKey:@"actor"]];
                                      // [dictUserInfo setObject:[[[dicts objectForKey:@"actor"] objectForKey:@"image"]objectForKey:@"url"] forKey:@"imageUrl"];


                                      if([delegate respondsToSelector:@selector(userPicChanged:)])
                                      {
                                          //send the delegate function with the amount entered by the user
                                          [delegate userPicChanged:[[[dicts objectForKey:@"actor"] objectForKey:@"image"]objectForKey:@"url"]];
                                      }



                                  }


                              } else {
                                  // fetch failed
                                  output = [error description];
                              }
                          }
                      }];

您必须将viewController的signIn.shouldFetchGoogleUserProfile设置为YES<代码>viewController.signIn.shouldFetchGoogleUserProfile=是请检查我的答案,如果不起作用请告诉我@为此,您必须将viewController的signIn.shouldFetchGoogleUserProfile设置为YES<代码>viewController.signIn.shouldFetchGoogleUserProfile=是请检查我的答案,如果不起作用请告诉我@托萨坎,你能展示一下你的尝试吗?我必须说,我还有另外一个问题,SDK显示“知道你在谷歌上是谁”。这是我的用户不想看到的。所以,同样的修复效果很好。非常感谢+1您能展示一下您的尝试吗?我必须说,我还有另外一个问题,SDK显示“知道你在谷歌上是谁”。这是我的用户不想看到的。所以,同样的修复效果很好。非常感谢