如何使用JSON框架解析iPhone SDK（XCode）中的JSON对象

我有这样的JSON对象：

{ "data":
  {"array":
    ["2",
       {"array":
          [
            {"clientId":"1","clientName":"Andy","job":"developer"},
            {"clientId":"2","clientName":"Peter","job":"carpenter"}
          ]
        }
     ]
   },
 "message":"MSG0001:Success",
 "status":"OK"
}

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我想使用JSON框架获取数组[0]值（2）和数组[1]值（clientId、clientName、job）。你知道怎么做吗？

假设你在项目中遵循了JSON框架，下面是你如何使用它（摘自：

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谢谢你的回答，我的问题解决了，我对你的代码做了一些修改，如下所示：

// Parse the string into JSON
NSDictionary *json = [myString JSONValue];

// Get all object
NSArray *items = [json valueForKeyPath:@"data.array"];
NSArray *array1 = [[items objectAtIndex:1] objectForKey:@"array"];
NSEnumerator *enumerator = [array1 objectEnumerator];
NSDictionary* item;
while (item = (NSDictionary*)[enumerator nextObject]) {
   NSLog(@"clientId = %@",  [item objectForKey:@"clientId"]);
   NSLog(@"clientName = %@",[item objectForKey:@"clientName"]);
   NSLog(@"job = %@",       [item objectForKey:@"job"]);
}

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如何在NSMUtableArray中存储此数据

while (item = (NSDictionary*)[enumerator nextObject]) {
   NSLog(@"clientId = %@",  [item objectForKey:@"clientId"]);//this 
   NSLog(@"clientName = %@",[item objectForKey:@"clientName"]);//this
   NSLog(@"job = %@",       [item objectForKey:@"job"]);//this
}

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我们需要一个类，比如MyData.h和MyData.m

//MyData.h
@interface MyData : NSObject {
    NSString *clientId;
    NSString *clientName;
    NSString *job;
}

@property (nonatomic, retain) NSString *clientId;
@property (nonatomic, retain) NSString *clientName;
@property (nonatomic, retain) NSString *job;

@end

//MyData.m
@implementation MyData

@synthesize clientId, clientName, job;

- (void)dealloc{    
    [clientId release];
    [clientName release];
    [job release];
    [super dealloc];
}

@end
//-------------------------------------

要存储我们的数据：

NSMutableArray *dataArray = [[NSMutableArray alloc]init];
while (item = (NSDictionary*)[enumerator nextObject]) {
    MyData *aMyData = [[MyData alloc] init];
    aMyData.clientId   = [item objectForKey:@"clientId"];
    aMyData.clientName = [item objectForKey:@"clientName"];
    aMyData.job        = [item objectForKey:@"job"];
    [dataArray addObject:aMyData];
    [aMyData release];
    aMyData = nil;
}

试试这个

while (item = (NSDictionary*)[enumerator nextObject]) {
NSMutableArray *myArray = [[NSMutableArray alloc] init];
[myArray AddObject:((NSDictionary*)[enumerator nextObject])];
}

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可以创建数据点的层次结构。例如，如果要获取JSON对象的内部数组，可以使用以下方法访问它：

NSArrray *objectArray = jsonObject[@"array"][@"2"][@"array"];

或者，你也可以做类似的事情。例如，在YelpAPI中，提供了一个企业的JSON。将这些业务放在一个数组中，您可以通过以下操作访问对象的不同元素：

NSString *businessLocation = [businessArray objectAtIndex: indexOfBusinessInArray][@"location"][@"display_address"];

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很抱歉，我可能听起来很粗鲁，但google for

iphone parse json

，第一次点击。这是一个很好的教程。它不应该是[[items objectAtIndex:1]objectForKey:@“clientId]”）；我有一个json格式的时间API如何使用，请帮助我。jsont（{“id”：“ntp-a1.nict.go.jp”，“it”：1232963971.248，“st”：1344228610.961，“leap”：34，“next”：1341100800，“step”：1}）

NSString *businessLocation = [businessArray objectAtIndex: indexOfBusinessInArray][@"location"][@"display_address"];