在Java中解密defuse/php encryption Crypto:：encryptWithPassword（）

我有一个PHP应用程序，它在MySQL数据库中存储一些敏感信息。为了保护这些信息，我使用库的

Crypto:：encryptWithPassword（）

方法如下：

<?php

// ... get sensitive data from user ...

$encrypted = base64_encode(Crypto::encryptWithPassword($sensitive, $password, true));

// ... store that data in database ...

但是，当我运行该代码时，出现以下错误：

Exception in thread "main" java.security.InvalidKeyException: Invalid AES key length: 4 bytes
    at com.sun.crypto.provider.AESCipher.engineGetKeySize(AESCipher.java:495)
    at javax.crypto.Cipher.passCryptoPermCheck(Cipher.java:1067)
    at javax.crypto.Cipher.checkCryptoPerm(Cipher.java:1025)
    at javax.crypto.Cipher.implInit(Cipher.java:801)
    at javax.crypto.Cipher.chooseProvider(Cipher.java:864)
    at javax.crypto.Cipher.init(Cipher.java:1249)
    at javax.crypto.Cipher.init(Cipher.java:1186)
    at com.example.test.app.Decrypt.main(Decrypt.java:24)

---

解密该数据的正确方法是什么？

“无效AES密钥长度：4字节”啊？啊。。。看起来我没有正确生成密钥。谢谢我会在找到正确的方法后更新问题。

Exception in thread "main" java.security.InvalidKeyException: Invalid AES key length: 4 bytes
    at com.sun.crypto.provider.AESCipher.engineGetKeySize(AESCipher.java:495)
    at javax.crypto.Cipher.passCryptoPermCheck(Cipher.java:1067)
    at javax.crypto.Cipher.checkCryptoPerm(Cipher.java:1025)
    at javax.crypto.Cipher.implInit(Cipher.java:801)
    at javax.crypto.Cipher.chooseProvider(Cipher.java:864)
    at javax.crypto.Cipher.init(Cipher.java:1249)
    at javax.crypto.Cipher.init(Cipher.java:1186)
    at com.example.test.app.Decrypt.main(Decrypt.java:24)