Java 线程同步。以正确的方式打印值

我找不到这个问题的解决办法。我在某一点上搞砸了，但不确定。请给出克服这一问题的建议

问题:

有三个数组，每个数组都分配给线程，输出应该按顺序

t1={1,4,7} t2={2,5,8} t3={3,6,9}

预期产量

out={1,2,3,4,5,6,7,8,9}

我尝试了什么：

public class Worker extends Thread {
    Worker next;
    int[] val;
    Object lock = new Object();

    Worker(int[] val) {

        this.val = val;
    }

    public void setnext(Worker next) {
        this.next = next;
    }

    @Override
    public void run() {
        for (int i = 0; i < val.length; i++) {
            synchronized (this) {
                synchronized (next) {

                    System.out.println(val[i]);
                    next.notify();

                }

                synchronized (this) {
                    try {

                        this.wait();
                    } catch (InterruptedException e) {
                        // TODO Auto-generated catch block
                        e.printStackTrace();
                    }
                }
            }
            synchronized(next){
                next.notify();
            }
        }
    }
}

---

试试我的版本。请注意，等待应始终用于循环中

public class Worker extends Thread {
    int[] val;
    Worker next;
    boolean ready;
    boolean go;

    Worker(int[] val) {
        this.val = val;
    }

    public void setNext(Worker next) {
        this.next = next;
    }

    @Override
    public void run() {
        synchronized (Worker.class) {
            ready = true;
            Worker.class.notifyAll();
            for (int i = 0; i < val.length; i++) {
                try {
                    while (!go) {
                        Worker.class.wait();
                    }
                    System.out.println(val[i]);
                    go = false;
                    next.go = true;
                    Worker.class.notifyAll();
                } catch (InterruptedException e) {
                }
            }
        }
    }

    public static void main(String[] args) throws Exception {
        Worker worker1 = new Worker(new int[] { 1, 4, 7 });
        Worker worker2 = new Worker(new int[] { 2, 5, 8 });
        Worker worker3 = new Worker(new int[] { 3, 6, 9 });

        worker1.setNext(worker2);
        worker2.setNext(worker3);
        worker3.setNext(worker1);

        worker1.start();
        worker2.start();
        worker3.start();

        synchronized (Worker.class) {
            while(!worker1.ready || !worker2.ready ||!worker3.ready ) {
                Worker.class.wait();
            }
            worker1.go = true;
            Worker.class.notifyAll();
        }
    }
}

---

试试我的版本。请注意，等待应始终用于循环中

public class Worker extends Thread {
    int[] val;
    Worker next;
    boolean ready;
    boolean go;

    Worker(int[] val) {
        this.val = val;
    }

    public void setNext(Worker next) {
        this.next = next;
    }

    @Override
    public void run() {
        synchronized (Worker.class) {
            ready = true;
            Worker.class.notifyAll();
            for (int i = 0; i < val.length; i++) {
                try {
                    while (!go) {
                        Worker.class.wait();
                    }
                    System.out.println(val[i]);
                    go = false;
                    next.go = true;
                    Worker.class.notifyAll();
                } catch (InterruptedException e) {
                }
            }
        }
    }

    public static void main(String[] args) throws Exception {
        Worker worker1 = new Worker(new int[] { 1, 4, 7 });
        Worker worker2 = new Worker(new int[] { 2, 5, 8 });
        Worker worker3 = new Worker(new int[] { 3, 6, 9 });

        worker1.setNext(worker2);
        worker2.setNext(worker3);
        worker3.setNext(worker1);

        worker1.start();
        worker2.start();
        worker3.start();

        synchronized (Worker.class) {
            while(!worker1.ready || !worker2.ready ||!worker3.ready ) {
                Worker.class.wait();
            }
            worker1.go = true;
            Worker.class.notifyAll();
        }
    }
}

---

向我们展示您尝试的代码添加了我尝试的代码。。感觉很混乱，所以我没有在前面添加..你打算用这段代码做什么？有很多其他的方法可以输出sequence@Spring.Rush好啊这是一个面试问题。。你能说。。还有什么其他方法可以做到这一点。如果您还没有，请阅读有效Java SE中的第68项和第69项。向我们展示您尝试过的代码添加了我尝试过的代码。。感觉很混乱，所以我没有在前面添加..你打算用这段代码做什么？有很多其他的方法可以输出sequence@Spring.Rush好啊这是一个面试问题。。你能说。。还有其他方法吗？如果您还没有，请阅读有效Java SE中的第68项和第69项。

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