Java 通过api将我的Android应用程序连接到本地主机上的服务器

我有个问题。我想将我的android应用程序连接到在本地主机上运行的PHP API。但在这段代码中，它总是抛出“Catch 1”，我甚至试图打印异常，但它没有工作。 以下是我的主要活动代码：

    package com.example.dbtest;

    import androidx.appcompat.app.AppCompatActivity;

    import android.os.AsyncTask;
    import android.os.Bundle;
    import android.util.Log;
    import android.view.View;
    import android.widget.Button;
    import android.widget.EditText;
    import android.widget.Toast;

    import org.json.JSONObject;

    import java.io.BufferedInputStream;
    import java.io.BufferedReader;
    import java.io.Console;
    import java.io.InputStream;
    import java.io.InputStreamReader;
    import java.net.HttpURLConnection;
    import java.net.URL;

    public class MainActivity extends AppCompatActivity {
    private EditText etUsername;
    private EditText etPassword;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        etUsername = findViewById(R.id.editTextUsername);
        etPassword = findViewById(R.id.editTextPassword);
    }

    public void register(View view) {
        Log.d("MainActivity", "Button clicked");
        String username = etUsername.getText().toString();
        String password = etPassword.getText().toString();
        String url = "http://app.test/test.php?username="+ username +"&password="+ password;
        new MyAsyncTaskgetNews().execute(url);
    }

    public class MyAsyncTaskgetNews extends AsyncTask<String, String, String> {
        @Override
        protected void onPreExecute() {
            //before works
        }

        @Override
        protected String  doInBackground(String... params) {
            Log.d("MainActivity","In Background");
            // TODO Auto-generated method stub
            try {
                String NewsData;
                //define the url we have to connect with
                URL url = new URL(params[0]);
                //make connect with url and send request
                HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
                //waiting for 7000ms for response
                urlConnection.setConnectTimeout(7000);//set timeout to 5 seconds

                try {
                    //getting the response data
                    InputStream in = new BufferedInputStream(urlConnection.getInputStream());
                    //convert the stream to string
                    NewsData = ConvertInputToStringNoChange(in);
                    //send to display data
                    publishProgress(NewsData);
                } finally {
                    //end connection
                    urlConnection.disconnect();
                }

            }catch (Exception ex)
            {
                Log.d("MainActivity", "Catch 1");
            }

            return null;
        }

        protected void onProgressUpdate(String... progress) {
            try {
                Log.d("MainActivity","In Progress");
                JSONObject json = new JSONObject(progress[0]);
                //display response data
                Toast.makeText(getApplicationContext(),json.getString("msg"),Toast.LENGTH_LONG).show();

            } catch (Exception ex) {
                Log.d("MainActivity","Catch 2");
            }
        }

        protected void onPostExecute(String  result2){
        }
    }

    // this method convert any stream to string
    public static String ConvertInputToStringNoChange(InputStream inputStream) {
        BufferedReader bureader=new BufferedReader( new InputStreamReader(inputStream));
        String line ;
        String linereultcal="";

        try{
            while((line=bureader.readLine())!=null) {

                linereultcal += line;

            }
            inputStream.close();


        }catch (Exception ex){}

        return linereultcal;
    }
}

有人知道问题出在哪里吗？感谢您的帮助

---

PS：对不起，我的英语不好，它不是我的母语。

我终于明白了

我的API在自定义virtualhost上运行，因此模拟器无法连接到自定义virtualhost。我将API移到“原始”localhost文件夹，并用代码编辑了我的url。 我的url现在如下所示：

String url = "http://10.0.2.2/test.php?username="+ username +"&password="+ password;

我发现的ip

10.0.2.2

是您的机器本地主机的快捷方式

---

如果有任何问题，我会尽力帮助

您应该记录异常并在问题中包含错误，而不是记录“Catch 1”。但我把它写了出来，并公布了我的解决方案。我希望它至少能帮助别人。

但在这段代码中，它总是抛出“Catch 1”

打印异常，而打印

Catch 1

对你没有帮助，你必须打印异常，以便你可以查看它并调试它。如上所述，我试图打印错误，但我没有打印错误！切勿以明文或使用MD5/SHA1存储密码！仅存储使用PHP创建的密码哈希，然后可以使用进行验证。看看这篇文章：了解更多关于

2020-06-19 11:03:21.467 3017-3663/com.example.dbtest W/System.err: java.net.ConnectException: Connection refused
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at java.net.PlainSocketImpl.socketConnect(Native Method)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at java.net.AbstractPlainSocketImpl.doConnect(AbstractPlainSocketImpl.java:334)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at java.net.AbstractPlainSocketImpl.connectToAddress(AbstractPlainSocketImpl.java:196)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at java.net.AbstractPlainSocketImpl.connect(AbstractPlainSocketImpl.java:178)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:356)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at java.net.Socket.connect(Socket.java:605)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.internal.Platform.connectSocket(Platform.java:113)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.Connection.connectSocket(Connection.java:196)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.Connection.connect(Connection.java:172)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.Connection.connectAndSetOwner(Connection.java:367)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.OkHttpClient$1.connectAndSetOwner(OkHttpClient.java:130)
2020-06-19 11:03:21.518 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.internal.http.HttpEngine.connect(HttpEngine.java:329)
2020-06-19 11:03:21.519 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.internal.http.HttpEngine.sendRequest(HttpEngine.java:246)
2020-06-19 11:03:21.519 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.internal.huc.HttpURLConnectionImpl.execute(HttpURLConnectionImpl.java:457)
2020-06-19 11:03:21.519 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.internal.huc.HttpURLConnectionImpl.getResponse(HttpURLConnectionImpl.java:405)
2020-06-19 11:03:21.519 3017-3663/com.example.dbtest W/System.err:     at com.android.okhttp.internal.huc.HttpURLConnectionImpl.getInputStream(HttpURLConnectionImpl.java:243)
2020-06-19 11:03:21.521 3017-3663/com.example.dbtest W/System.err:     at com.example.dbtest.MainActivity$MyAsyncTaskgetNews.doInBackground(MainActivity.java:69)
2020-06-19 11:03:21.521 3017-3663/com.example.dbtest W/System.err:     at com.example.dbtest.MainActivity$MyAsyncTaskgetNews.doInBackground(MainActivity.java:44)
2020-06-19 11:03:21.522 3017-3663/com.example.dbtest W/System.err:     at android.os.AsyncTask$2.call(AsyncTask.java:305)
2020-06-19 11:03:21.522 3017-3663/com.example.dbtest W/System.err:     at java.util.concurrent.FutureTask.run(FutureTask.java:237)
2020-06-19 11:03:21.523 3017-3663/com.example.dbtest W/System.err:     at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:243)
2020-06-19 11:03:21.523 3017-3663/com.example.dbtest W/System.err:     at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1133)
2020-06-19 11:03:21.523 3017-3663/com.example.dbtest W/System.err:     at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:607)
2020-06-19 11:03:21.523 3017-3663/com.example.dbtest W/System.err:     at java.lang.Thread.run(Thread.java:761)

String url = "http://10.0.2.2/test.php?username="+ username +"&password="+ password;