Java OpenCV中两个矩形的并集
国家: 除了类成员之外,还可以对 矩形被实现为: [……]Java OpenCV中两个矩形的并集,java,opencv,operator-overloading,Java,Opencv,Operator Overloading,国家: 除了类成员之外,还可以对 矩形被实现为: [……] rect=rect1 | rect2(包含rect2和rect3的最小面积矩形) 但是,该代码: Rect box1 = new Rect(); Rect box2 = new Rect(); Rect unionBox = new Rect(); unionBox = box1 | box2; 导致此错误的原因: 运算符“|”不能应用于“org.opencv.core.Rect”、“org.opencv.core.Rect”
- rect=rect1 | rect2(包含rect2和rect3的最小面积矩形)
Rect box1 = new Rect();
Rect box2 = new Rect();
Rect unionBox = new Rect();
unionBox = box1 | box2;
导致此错误的原因:
运算符“|”不能应用于“org.opencv.core.Rect”、“org.opencv.core.Rect”
如何正确地合并两个(或更好:多个)
Rect
s?JAVA不支持使用运算符的AFAIK
<>我建议使用,但是你应该知道,在下面的C++代码中有一个像素差异。
#include "opencv2/imgproc/imgproc.hpp"
#include "opencv2/highgui/highgui.hpp"
#include <iostream>
using namespace cv;
using namespace std;
int main(int argc, char** argv)
{
Rect a(10,10,20,20);
Rect b(11,11,20,20);
vector<Point> pts;
pts.push_back(a.tl());
pts.push_back(a.br());
pts.push_back(b.tl());
pts.push_back(b.br());
Rect boundingRect_result = boundingRect( pts );
Rect operator_result = a | b;
cout << "Rect a: " << a << endl;
cout << "Rect b: " << b << endl;
cout << "\nRect Points a b:\n" << pts << endl;
cout << "\nboundingRect result : " << boundingRect_result << endl;
cout << "result a | b : " << operator_result << endl;
return 0;
}
(我不熟悉JAVA,但尝试编写下面的代码进行测试)
结果就像{10,10,22x22}
另一种选择是用JAVA编写自己的函数。可以转换为JAVA的
Rect a: [20 x 20 from (10, 10)]
Rect b: [20 x 20 from (11, 11)]
Rect Points a b:
[10, 10;
30, 30;
11, 11;
31, 31]
boundingRect result : [22 x 22 from (10, 10)]
result a | b : [21 x 21 from (10, 10)]
Rect r1 = new Rect(10,10,20,20);
Rect r2 = new Rect(11,11,20,20);
Point[] rects_pts = new Point[4];
rects_pts[0] = r1.tl();
rects_pts[1] = r1.br();
rects_pts[2] = r2.tl();
rects_pts[3] = r2.br();
MatOfPoint mof = new MatOfPoint();
mof.fromArray(rects_pts);
Rect union = Imgproc.boundingRect(mof);
System.out.print( union);