Java 如何使用ApachePOI从excel工作表的透视表中访问单元格值?
如何使用ApachePOI从excel工作表的透视表中访问单元格值? 我尝试使用XSSFPivotTable.getPivotTables,但无法访问单元格值。 Book1.xlsx是excel工作簿,在工作表1上有一个数据透视表Java 如何使用ApachePOI从excel工作表的透视表中访问单元格值?,java,apache-poi,Java,Apache Poi,如何使用ApachePOI从excel工作表的透视表中访问单元格值? 我尝试使用XSSFPivotTable.getPivotTables,但无法访问单元格值。 Book1.xlsx是excel工作簿,在工作表1上有一个数据透视表 FileInoutStream input=newfileinputstream(新文件(Book1.xlsx)); XSSF工作簿wb=新XSSF工作簿(输入); XSSFSheet sh=wb.getSheet(“Sheet1”); XSSFPivotTable
FileInoutStream input=newfileinputstream(新文件(Book1.xlsx));
XSSF工作簿wb=新XSSF工作簿(输入);
XSSFSheet sh=wb.getSheet(“Sheet1”);
XSSFPivotTable pt=sh.getPivotTables().get(0)代码>
在此之前无法访问pt pivot表中的单元格 下面是访问数据透视表标题和数据的自定义方法,我不确定,但我找不到通过库访问数据的方法,在我读到的一些东西上搜索,上面说它还不受支持
让我们看看我做了什么:
输入文件:
列的数字转换字母:
Map<String, Integer> map = new HashMap<String, Integer>() {
{
int index =1;
for (char ch = 'A'; ch <= 'Z'; ++ch) {
put(String.valueOf(ch), index);
index++;
}
}
};
完整代码:
public static void main(String[] args) {
//tranform letters in numbers for columns
Map<String, Integer> map = new HashMap<String, Integer>() {
{
int index =1;
for (char ch = 'A'; ch <= 'Z'; ++ch) {
put(String.valueOf(ch), index);
index++;
}
}
};
try {
FileInputStream input = new FileInputStream(new File("C:\\Desktop\\ook.xlsx"));
XSSFWorkbook wb = new XSSFWorkbook(input);
XSSFSheet sh = wb.getSheet("Sheet1");
Iterator<Row> rowIterator = sh.iterator();
ArrayList columndata = new ArrayList<>();
java.util.List<XSSFPivotTable> l = sh.getPivotTables();
String range = l.get(0).getCTPivotTableDefinition().getLocation().getRef(); //F6:G7 rows/cols reference - case of our sheet
//determinate range of table
int firstcol = map.get(range.substring(0, 1));
int firstrow = Integer.parseInt(range.substring(1, 2));
int lastcol = map.get(range.substring(3, 4));
int lastrow = Integer.parseInt(range.substring(4, 5));
while (rowIterator.hasNext()) {
Row row = rowIterator.next();
if(checkrightrowcol(row.getRowNum()+1, firstrow, lastrow)){
Iterator<Cell> cellIterator = row.cellIterator();
while (cellIterator.hasNext()) {
Cell cell = cellIterator.next();
if(checkrightrowcol(cell.getColumnIndex()+1,firstcol,lastcol)){
switch(cell.getCellType()){
case Cell.CELL_TYPE_NUMERIC: // numeric value
System.out.println(cell.getNumericCellValue());
break;
case Cell.CELL_TYPE_STRING: // String Value
System.out.println(cell.getStringCellValue());
break;
//..add more
}
}
}
}
}
} catch (IOException e) {
e.printStackTrace();
}
}
如果它在表数据中返回true im,则主要使用“+1”,因为行和列索引从“0”开始
结果:
你好。请添加一个MVCE(),这样我们可以更好地了解您正在尝试做什么以及问题可能在哪里。@FabianSchöner添加了MCVE。您得到答案了吗?您得到解决方案了吗?我尝试了上面的代码,但遇到了一个奇怪的问题。如果pivot是在excel中手动创建的,则能够获得正确的范围,例如K6:N21,但如果pivot是以编程方式创建的,则可以获得范围K6:L7。就为了记录,pivot表是用程序正确创建的。我明白了,我不确定,但这可能是库的一个限制
<xml-fragment name="PivotTable7" cacheId="24" applyNumberFormats="0" applyBorderFormats="0" applyFontFormats="0" applyPatternFormats="0" applyAlignmentFormats="0" applyWidthHeightFormats="1" dataCaption="Values" updatedVersion="6" minRefreshableVersion="3" useAutoFormatting="1" itemPrintTitles="1" createdVersion="6" indent="0" outline="1" outlineData="1" multipleFieldFilters="0" xmlns:main="http://schemas.openxmlformats.org/spreadsheetml/2006/main">
<main:location ref="F6:G7" firstHeaderRow="0" firstDataRow="1" firstDataCol="0"/>
<main:pivotFields count="2">
<main:pivotField dataField="1" subtotalTop="0" showAll="0">
<main:items count="2">
<main:item x="0"/>
<main:item t="default"/>
</main:items>
</main:pivotField>
<main:pivotField dataField="1" subtotalTop="0" showAll="0"/>
</main:pivotFields>
<main:rowItems count="1">
<main:i/>
</main:rowItems>
<main:colFields count="1">
<main:field x="-2"/>
</main:colFields>
<main:colItems count="2">
<main:i>
<main:x/>
</main:i>
<main:i i="1">
<main:x v="1"/>
</main:i>
</main:colItems>
<main:dataFields count="2">
<main:dataField name="A" fld="0" baseField="0" baseItem="1"/>
<main:dataField name="B" fld="1" baseField="0" baseItem="1"/>
</main:dataFields>
<main:pivotTableStyleInfo name="PivotStyleLight16" showRowHeaders="1" showColHeaders="1" showRowStripes="0" showColStripes="0" showLastColumn="1"/>
<main:extLst>
<main:ext uri="{962EF5D1-5CA2-4c93-8EF4-DBF5C05439D2}" xmlns:x14="http://schemas.microsoft.com/office/spreadsheetml/2009/9/main">
<x14:pivotTableDefinition hideValuesRow="1" xmlns:xm="http://schemas.microsoft.com/office/excel/2006/main"/>
</main:ext>
<main:ext uri="{747A6164-185A-40DC-8AA5-F01512510D54}" xmlns:xpdl="http://schemas.microsoft.com/office/spreadsheetml/2016/pivotdefaultlayout">
<xpdl:pivotTableDefinition16 SubtotalsOnTopDefault="0"/>
</main:ext>
</main:extLst>
</xml-fragment>
String range = l.get(0).getCTPivotTableDefinition().getLocation().getRef(); //F6:G7 rows/cols reference - case of our sheet
//determinate range of table
int firstcol = map.get(range.substring(0, 1));
int firstrow = Integer.parseInt(range.substring(1, 2));
int lastcol = map.get(range.substring(3, 4));
int lastrow = Integer.parseInt(range.substring(4, 5));
public static void main(String[] args) {
//tranform letters in numbers for columns
Map<String, Integer> map = new HashMap<String, Integer>() {
{
int index =1;
for (char ch = 'A'; ch <= 'Z'; ++ch) {
put(String.valueOf(ch), index);
index++;
}
}
};
try {
FileInputStream input = new FileInputStream(new File("C:\\Desktop\\ook.xlsx"));
XSSFWorkbook wb = new XSSFWorkbook(input);
XSSFSheet sh = wb.getSheet("Sheet1");
Iterator<Row> rowIterator = sh.iterator();
ArrayList columndata = new ArrayList<>();
java.util.List<XSSFPivotTable> l = sh.getPivotTables();
String range = l.get(0).getCTPivotTableDefinition().getLocation().getRef(); //F6:G7 rows/cols reference - case of our sheet
//determinate range of table
int firstcol = map.get(range.substring(0, 1));
int firstrow = Integer.parseInt(range.substring(1, 2));
int lastcol = map.get(range.substring(3, 4));
int lastrow = Integer.parseInt(range.substring(4, 5));
while (rowIterator.hasNext()) {
Row row = rowIterator.next();
if(checkrightrowcol(row.getRowNum()+1, firstrow, lastrow)){
Iterator<Cell> cellIterator = row.cellIterator();
while (cellIterator.hasNext()) {
Cell cell = cellIterator.next();
if(checkrightrowcol(cell.getColumnIndex()+1,firstcol,lastcol)){
switch(cell.getCellType()){
case Cell.CELL_TYPE_NUMERIC: // numeric value
System.out.println(cell.getNumericCellValue());
break;
case Cell.CELL_TYPE_STRING: // String Value
System.out.println(cell.getStringCellValue());
break;
//..add more
}
}
}
}
}
} catch (IOException e) {
e.printStackTrace();
}
}
public static boolean checkrightrowcol(int n , int start, int end){
while (start!=end){
if(n == start || n == end)
return true;
start++;
}
return false;
}