“在哪里放线?”;accept()&引用;在多线程java程序中
我正在尝试创建一个程序,在这个程序中,服务器和客户端可以同时相互发送和接收消息(就像两个使用手机的人可以互相发短信一样) 有三个文件(主功能文件、服务器文件和客户机文件),我现在只想关注服务器和主文件 服务器文件的问题是有两个独立的线程,每个线程都有自己的“run”函数,因此我想知道应该将“socket.accept()”行放在哪里,以便使它们都能工作(也许以前,以某种方式全局运行?) 运行服务器的命令行参数包括“在哪里放线?”;accept()&引用;在多线程java程序中,java,multithreading,sockets,Java,Multithreading,Sockets,我正在尝试创建一个程序,在这个程序中,服务器和客户端可以同时相互发送和接收消息(就像两个使用手机的人可以互相发短信一样) 有三个文件(主功能文件、服务器文件和客户机文件),我现在只想关注服务器和主文件 服务器文件的问题是有两个独立的线程,每个线程都有自己的“run”函数,因此我想知道应该将“socket.accept()”行放在哪里,以便使它们都能工作(也许以前,以某种方式全局运行?) 运行服务器的命令行参数包括 java DirectMessengerCombined -l 3000 如果“
java DirectMessengerCombined -l 3000
如果“-l”不存在,则它将作为客户端运行
我认为服务器文件的流程是这样的(psuedo代码注释)(如果我错了,请纠正我)
根据此流,是否可以从线程接受第一次运行方法之外的连接?也许在构造器中
服务器代码:
import java.io.*;
import java.net.*;
import java.util.*;
import javax.imageio.IIOException;
public class DirectMessengerServer
{
private String[] serverArgs;
private static Socket socket;
public boolean keepRunning = true;
public DirectMessengerServer(String[] args) throws IOException
{
// should serverSocket.accept() go here???
// set the instance variable
this.serverArgs = args;
int port_number1 = Integer.valueOf(serverArgs[1]);
ServerSocket serverSocket = new ServerSocket(port_number1);
socket = serverSocket.accept();
}
public String[] ServerRun(String[] args)
{
serverArgs = args;
serverArgs = Arrays.copyOf(args, args.length);
return serverArgs;
}
// should serverSocket.accept() go here???
Thread ServerRecieve = new Thread();
//If i put serverSocket.accept() in both the run methods, won't that cause an "Address already in use error"?
//run method of ServerRecieve
public void run(String args[])
{
System.out.println("Server recieve thread is now running");
try
{
while(keepRunning)
{
//Reading the message from the client
InputStream is = socket.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String MessageFromClient = br.readLine();
System.out.println("Message received from client: "+ MessageFromClient);
}
}
catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
finally
{
try
{
socket.close();
}
catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
Thread ServerSend = new Thread ();
//Run method of ServerSend
public void run()
{
while(keepRunning)
{
System.out.println("Server sending thread is now running");
try
{
//Send the message to the server
OutputStream os = socket.getOutputStream();
OutputStreamWriter osw = new OutputStreamWriter(os);
BufferedWriter bw = new BufferedWriter(osw);
//creating message to send from standard input
String newmessage = "";
try
{
// input the message from standard input
BufferedReader input= new BufferedReader(
new InputStreamReader(System.in));
String line = "";
line= input.readLine();
newmessage += line + " ";
}
catch ( Exception e )
{
System.out.println( e.getMessage() );
}
String sendMessage = newmessage;
bw.write(sendMessage + "\n");
bw.flush();
System.out.println("Message sent to client: "+sendMessage);
}
catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
finally
{
}
}
}
}
主功能文件的代码:
import java.io.IOException;
public class DirectMessengerCombined
{
public static void main(String[] args) throws IOException
{
DirectMessengerClient Client1 = new DirectMessengerClient();
// Thread t1 = new Thread(Client1);
DirectMessengerServer Server1 = new DirectMessengerServer(args);
//DirectMessengerServer Server1 = new DirectMessengerServer(args[1], null, 0);
for (int i = 0; i < args.length; i++)
{
if(!args[0].equals("-l"))
{
Client1.ClientRun(args);
}
switch (args[0].charAt(0))
{
case '-':
if(args[0].equals("-l"))
{
Server1.ServerRun(args);
}
}
i=args.length + 20;
}
}
}
import java.io.IOException;
公共类DirectMessenger
{
公共静态void main(字符串[]args)引发IOException
{
DirectMessenger客户端1=新的DirectMessenger客户端();
//线程t1=新线程(客户端1);
DirectMessenger服务器1=新的DirectMessenger服务器(args);
//DirectMessenger服务器Server1=新的DirectMessenger服务器(args[1],null,0);
对于(int i=0;i
我的问题是:在代码中,哪里是接受连接的正确位置,以便两个运行方法都能够像它们都被连接一样工作?通常,您会将它放在自己线程的循环中,并且您将为每个接受的连接启动一个新线程。我明白了。ThreadName.start()的位置;寻找外线程和内线程?是否类似于
threadlistingloop=new Thread();public void run(String args[]){try{while(keepRunning){int port_number1=Integer.valueOf(serverArgs[1]);ServerSocket ServerSocket=new ServerSocket(port_number1);socket=ServerSocket.accept();Thread receivingloop=new Thread();void run(){//code to loop reading/receivng messages}
不要让我在注释中对代码进行注释。你可以自己看到它完全难以辨认。将它发布在你的问题或其他问题中,在那里可以格式化并阅读。
import java.io.IOException;
public class DirectMessengerCombined
{
public static void main(String[] args) throws IOException
{
DirectMessengerClient Client1 = new DirectMessengerClient();
// Thread t1 = new Thread(Client1);
DirectMessengerServer Server1 = new DirectMessengerServer(args);
//DirectMessengerServer Server1 = new DirectMessengerServer(args[1], null, 0);
for (int i = 0; i < args.length; i++)
{
if(!args[0].equals("-l"))
{
Client1.ClientRun(args);
}
switch (args[0].charAt(0))
{
case '-':
if(args[0].equals("-l"))
{
Server1.ServerRun(args);
}
}
i=args.length + 20;
}
}
}