Java 如何分离迭代器的元素?

Java 如何分离迭代器的元素?,java,arraylist,hashmap,Java,Arraylist,Hashmap,我想随机生成时间和数字。。这里我用hashmap生成了一些记录。现在我可以生成数字,但我不能将它们分开。我必须将这些值分开,以便在数据库中设置这些值 这是我的密码 public class DateTimePopulation { private Random rand = new Random(); private Date theDay; private String callDuration = null; private String endDay = null; SimpleDat

我想随机生成时间和数字。。这里我用hashmap生成了一些记录。现在我可以生成数字,但我不能将它们分开。我必须将这些值分开,以便在数据库中设置这些值

这是我的密码

public class DateTimePopulation {

private Random rand = new Random(); 
private Date theDay;
private String callDuration = null;
private String endDay = null;
SimpleDateFormat mytimeFormat = new SimpleDateFormat("HH:mm:ss");

public static void main(String[] args) throws ParseException {
    DateTimePopulation d = new DateTimePopulation();
    for (int i = 1; i <= 3; i++) {
        Map rec = d.getRecord();
    for (int j = 0; j < rec.size(); j++) {
            Collection c = rec.values();
            Iterator itr = c.iterator();
            int count=0;
            while (itr.hasNext()) {                 
                Object element=itr.next();
                System.out.println(element); 
            }
            System.out.println();
        }
    }
}

private Map getRecord() {
    Map<String, Object> rec = new LinkedHashMap<String, Object>();
    Date startDate;
    try {
        startDate = getRandStartDate();
        rec.put("StartTime", startDate);

        int start = 7200000, end = 0;
        int duration = getRandDuration(start, end);
        rec.put("Duration", duration);

        Date endDate = getRandEndDate(startDate, duration);
        rec.put("EndTime", endDate);

    } catch (ParseException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    return rec;
}



private Date getRandEndDate(Date startDate, int duration) {
    Random r = new Random();
    int ranSec = r.nextInt(duration - 0) + 0;
    return new Date(startDate.getTime() + ranSec * 1000);
}

private int getRandDuration(int High, int Low) {
    Random r = new Random();
    return r.nextInt(High - Low) + Low;
}

private Date getRandStartDate() throws ParseException {
    Date theDay = new SimpleDateFormat("yyyyMMdd hh:mm:ss")
            .parse("20130101 00:00:00");
    int High = 60 * 60 * 24 * 30 * 6;
    Random r = new Random();
    int Low = 10;
    int R = r.nextInt(High - Low) + Low;

    return new Date(theDay.getTime() + R * 1000);
}

}

尝试泛化此代码:

 private Map getRecord() {
        Map<String, Object> rec = new LinkedHashMap<String, Object>();
        Date startDate;
        try {
            startDate = getRandStartDate();
            rec.put("StartTime", startDate);

            int start = 7200000, end = 0;
            int duration = getRandDuration(start, end);
            rec.put("Duration", duration);

            Date endDate = getRandEndDate(startDate, duration);
            rec.put("EndTime", endDate);

        } catch (ParseException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        return rec;
    }
另见:

public class DateInterval {
    private Date startDate;
    private Date endDate;
    private int duration;

    public DateInterval(Date startDate, Date endDate, int duration) {
        this.startDate = startDate;
        this.endDate = endDate;
        this.duration = duration;
    }

    public Date getStartDate() {
        return startDate;
    }

    public Date getEndDate() {
        return endDate;
    }

    public int getDuration() {
        return duration;
    }
}

我的意思是,你不需要地图来达到这个目的,使用你自己的实体。如果您需要在集合中保存所有实体,请使用Map with DB UUID作为键或列表。

首先,您的设计从一开始就很奇怪-为什么要在实例上调用
getRecord()
,而它对您调用它的对象的字段没有任何作用

此外,当您在地图上迭代时,您实际上在同一地图上迭代了3次:

for (int j = 0; j < rec.size(); j++) {
    Collection c = rec.values();
    Iterator itr = c.iterator();
    int count=0;
    while (itr.hasNext()) {                 
        Object element=itr.next();
        System.out.println(element); 
    }
    System.out.println();
}

基本上,我强烈建议您后退一步,重新审视您的整个设计。您可能会发现从头开始比更改现有代码更好。

您所说的“分隔值”是什么意思?真的不清楚你想做什么。如果您试图将日期和时间拆分为其日期和时间组件,则这与迭代器无关。我希望将星期二1月8日11:01:57 IST 2013存储在stime中,将6074479存储在dur中,将星期五1月18日12:56:24 IST 2013存储在etime中。。。输出就像一组值,我必须将它们分开。。
public class DateInterval {
    private Date startDate;
    private Date endDate;
    private int duration;

    public DateInterval(Date startDate, Date endDate, int duration) {
        this.startDate = startDate;
        this.endDate = endDate;
        this.duration = duration;
    }

    public Date getStartDate() {
        return startDate;
    }

    public Date getEndDate() {
        return endDate;
    }

    public int getDuration() {
        return duration;
    }
}
for (int j = 0; j < rec.size(); j++) {
    Collection c = rec.values();
    Iterator itr = c.iterator();
    int count=0;
    while (itr.hasNext()) {                 
        Object element=itr.next();
        System.out.println(element); 
    }
    System.out.println();
}
System.out.println("Start: " + map.get("StartTime");
System.out.println("Duration: " + map.get("Duration");
System.out.println("End: " + map.get("EndTime");