在Java中查找字符数组大小时出错

我刚刚开始使用Java，我不明白为什么会有这样的代码：

char WORDS[][] = {"jazz", "buzz", "hajj", "fuzz", "jinx", "jazzy", "fuzzy", "faffs", "fizzy", "jiffs", "jazzed", "buzzed", "jazzes", "faffed", "fizzed", "jazzing", "buzzing", "jazzier", "faffing", "fuzzing"};
char comp[] = WORDS[rand.nextInt(WORDS.length)];
char compHidden[comp.length];

产生以下错误：

- Syntax error on token "[", = expected
- Type mismatch: cannot convert from int 
 to char
- Syntax error on token "]", delete this 
 token

---

都在第三行。为什么会这样？还有其他方法可以找到字符数组的长度吗？

这里需要赋值，如：

char compHidden[] = new char[comp.length];

---

WORDS

数组不是作为多维数组实例化的，而是作为常规的

char[]

实例化的，应该这样声明。此外，数组的类型不应该是

char[]

，而应该是

String[]

，因为指定了数组的类型

更改：

char WORDS[][] = {"jazz", "buzz", "hajj", "fuzz", "jinx", "jazzy", "fuzzy", "faffs", "fizzy", "jiffs", "jazzed", "buzzed", "jazzes", "faffed", "fizzed", "jazzing", "buzzing", "jazzier", "faffing", "fuzzing"};

到

---

char WORDS[][]

应该是

String WORDS[]

在Java中，

char[]

与

String

不同。与C样式字符串不同，Java中的字符序列并不表示字符数组。另外，最后一行不是有效的Java。必须在右侧使用

new

指定数组的长度，如

char[]compHidden=new char[comp.length]

@subrajyotimajumder注意，在更正的示例中，数组声明为

String[]

String WORDS[] = {"jazz", "buzz", "hajj", "fuzz", "jinx", "jazzy", "fuzzy", "faffs", "fizzy", "jiffs", "jazzed", "buzzed", "jazzes", "faffed", "fizzed", "jazzing", "buzzing", "jazzier", "faffing", "fuzzing"};