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Java 无法在servlet中解析参数_Java_Jsp_Servlets - Fatal编程技术网

Java 无法在servlet中解析参数

Java 无法在servlet中解析参数,java,jsp,servlets,Java,Jsp,Servlets,我正在尝试从jsp page-index.jsp获取凭据 在我的servlet LoginServletwhen包dao下我使用 String userName = request.getParameter(usrnm_gtalk); String password = request.getParameter(password_gtalk); 它说,usrnm_gtalk和password_gtalk无法解析 在我的jsp中 <form name="LoginForm" method=

我正在尝试从jsp page-index.jsp获取凭据 在我的servlet LoginServletwhen包dao下我使用

String userName = request.getParameter(usrnm_gtalk);
String password = request.getParameter(password_gtalk);
它说,
usrnm_gtalk
password_gtalk
无法解析

在我的jsp中

<form name="LoginForm" method="post" action="/dao/LoginServlet>   
<input type="text" name="usrnm_gtalk"/>
<input type="password" name="password_gtalk" />

您需要用双引号将它们表示为字符串,而不是不存在的变量(正如编译器试图告诉您的那样)

另见:
  • -包含一个小小的hello world
<welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <servlet>
    <description></description>
    <display-name>LoginServlet</display-name>
    <servlet-name>LoginServlet</servlet-name>
    <servlet-class>dao.LoginServlet</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>LoginServlet</servlet-name>
    <url-pattern>/Login</url-pattern>
  </servlet-mapping>
String userName = request.getParameter("usrnm_gtalk"); 
String password = request.getParameter("password_gtalk");