Java 具有不同数组参数的构造函数
我试图用数组参数创建不同的构造函数。数组具有不同的维度。但实际上,二维构造函数可以随时调用Java 具有不同数组参数的构造函数,java,arrays,constructor,overloading,junit5,Java,Arrays,Constructor,Overloading,Junit5,我试图用数组参数创建不同的构造函数。数组具有不同的维度。但实际上,二维构造函数可以随时调用 public Network(String [] adjacentMatrixRows) throws AdjacentMatrixCreationExeption { this.adjacentMatrix = new int[adjacentMatrixRows.length][]; String [][] stringMatrix = new String[adjacentMatri
public Network(String [] adjacentMatrixRows) throws AdjacentMatrixCreationExeption {
this.adjacentMatrix = new int[adjacentMatrixRows.length][];
String [][] stringMatrix = new String[adjacentMatrixRows.length][];
for (int i = 0; i < adjacentMatrixRows.length; i++) {
stringMatrix[i] = adjacentMatrixRows[i].trim().split(" ");
this.adjacentMatrix[i] = new int[stringMatrix[i].length];
}
for (int i = 0; i < stringMatrix.length; i++){
for (int j = 0; j < stringMatrix[i].length; j++) {
try {
this.adjacentMatrix[i][j] = Integer.parseInt(stringMatrix[i][j]);
}
catch (NumberFormatException e){
throw new AdjacentMatrixCreationExeption("Wrong data format in String[].");
}
}
}
}
public Network(String[][] adjacentMatrix) throws AdjacentMatrixCreationExeption {
this.adjacentMatrix = new int [adjacentMatrix.length][];
for (int i = 0; i < adjacentMatrix.length; i++){
this.adjacentMatrix[i] = new int[adjacentMatrix[i].length];
for (int j = 0; j < adjacentMatrix[i].length; j++) {
try {
this.adjacentMatrix[i][j] = Integer.parseInt(adjacentMatrix[i][j]);
}
catch (NumberFormatException e){
throw new AdjacentMatrixCreationExeption("Wrong data format in String[][].");
}
}
}
}
JUnit测试的输出:
` Throwable exception = assertThrows(AdjacentMatrixCreationExeption.class, ()-> {
Network network = new Network(new String [][]{{"1", "a"},{"1", "1"}});});
assertEquals("Wrong data format in String[][].", exception.getMessage());`
Throwable exception2 = assertThrows(AdjacentMatrixCreationExeption.class, ()-> {
Network network = new Network(new String []{"1", "a", "1", "1"});});
assertEquals("Wrong data format in String[].", exception.getMessage());
org.opentest4j.AssertionFailedError: expected: <Wrong data format in String[].> but was: <Wrong data format in String[][].>
Expected :Wrong data format in String[].
Actual :Wrong data format in String[][].
org.opentest4j.AssertionFailedError:应为:但为:
应为:字符串[]中的数据格式错误。
实际值:字符串[]中的数据格式错误。
我做了下面的测试
public class Test {
public static void main(String[] args) {
String[] array = new String[1];
String[][] array2D = new String[1][1];
Network n1 = new Network(array);
Network n2 = new Network(array2D);
}
}
这是一个包含两个构造函数的网络类:
class Network {
public Network (String [] adjacentMatrixRows){
System.out.println("Array");
}
public Network (String [][] adjacentMatrixRows){
System.out.println("2D Array");
}
}
我得到了以下输出:
排列
二维阵列
我找到了答案!在我的JUnit测试中,我总是使用一个名为“exception”的异常。但在第二次测试中,我不得不使用“例外2”
谢谢大家。问题已经解决。您在这里要求澄清,因此您应该将此作为评论发布(您可以链接到例如ideone示例来演示您描述的行为,而不是试图在评论中发布)。我删除了我的问题,现在我的帖子是一个答案。请在你的问题中说明你如何尝试调用构造函数。@AndyTurner,已更新。我已经测试了你的代码,但它给了我编译错误。请在发布网络类的完整代码之前修复错误。@KDavid Valerio,你在说什么?它在我的电脑里编译。如果您谈论的是JUnit测试,那么它们必须使用“@”测试站运行
Throwable exception2 = assertThrows(AdjacentMatrixCreationExeption.class, ()-> {
Network network = new Network(new String []{"1", "a", "1", "1"});});
assertEquals("Wrong data format in String[].", exception2.getMessage());