Javascript 在Asp.Net内核中使用Ajax上传文件
大家好, 我试图使用ajax将文件从客户端上传到服务器端(asp.NETCore)控制器,但我有一个空值 以下是我的html和javascript代码:Javascript 在Asp.Net内核中使用Ajax上传文件,javascript,c#,jquery,asp.net,ajax,Javascript,C#,Jquery,Asp.net,Ajax,大家好, 我试图使用ajax将文件从客户端上传到服务器端(asp.NETCore)控制器,但我有一个空值 以下是我的html和javascript代码: <input type="file" id="myfile" class="required" /> <button type="button" class="btn btn-info" onclick="uploadcsvfile()"> <script> function uploadcsvfi
<input type="file" id="myfile" class="required" />
<button type="button" class="btn btn-info" onclick="uploadcsvfile()">
<script>
function uploadcsvfile() {
var myfile= document.getElementById("myfile");
var formData = new FormData();
if (myfile.files.length > 0) {
for (var i = 0; i < myfile.files.length; i++) {
formData.append('file-' + i, myfile.files[i]);
}
}
$.ajax({
url: "/MyController/UploadFile/",
type: "POST",
dataType: "json",
data: formData,
contentType: false,
processData: false,
success: function(data){
},
error: function (data) {
}
})
}
</script>
函数uploadcsvfile(){
var myfile=document.getElementById(“myfile”);
var formData=new formData();
如果(myfile.files.length>0){
对于(var i=0;i
这是我使用IFormFile的控制器
public async Task<JsonResult> UploadFile(IFormFile formData)
{
// do something here
}
public异步任务上传文件(formfile formData)
{
//在这里做点什么
}
提前谢谢你 以下是一种将文件发布到控制器操作的简单方法 查看:
var formData = new FormData();
formData.append('file', $('#myfile')[0].files[0]); // myFile is the input type="file" control
var _url = '@Url.Action("UploadFile", "MyController")';
$.ajax({
url: _url,
type: 'POST',
data: formData,
processData: false, // tell jQuery not to process the data
contentType: false, // tell jQuery not to set contentType
success: function (result) {
},
error: function (jqXHR) {
},
complete: function (jqXHR, status) {
}
});
[HttpPost]
public ActionResult UploadFile(IFormFile file)
{
List<string> errors = new List<string>(); // added this just to return something
if (file != null)
{
// do something
}
return Json(errors, JsonRequestBehavior.AllowGet);
}
控制器:
var formData = new FormData();
formData.append('file', $('#myfile')[0].files[0]); // myFile is the input type="file" control
var _url = '@Url.Action("UploadFile", "MyController")';
$.ajax({
url: _url,
type: 'POST',
data: formData,
processData: false, // tell jQuery not to process the data
contentType: false, // tell jQuery not to set contentType
success: function (result) {
},
error: function (jqXHR) {
},
complete: function (jqXHR, status) {
}
});
[HttpPost]
public ActionResult UploadFile(IFormFile file)
{
List<string> errors = new List<string>(); // added this just to return something
if (file != null)
{
// do something
}
return Json(errors, JsonRequestBehavior.AllowGet);
}
[HttpPost]
public ActionResult上载文件(IFormFile文件)
{
List errors=new List();//添加此项只是为了返回某些内容
如果(文件!=null)
{
//做点什么
}
返回Json(错误,JsonRequestBehavior.AllowGet);
}
您只需指定文件输入“name”属性(与ASP.NET控制器中的变量名相同)。
HTML:
对于AJAX请求,您需要在FormData对象中指定适当的名称。详细解释如下:
浏览器端代码:
HTML
服务器端代码:
[HttpPost]
公共异步任务索引(IList文件)
{
foreach(文件中的文件源)
{
string filename=ContentDispositionHeaderValue.Parse(source.ContentDisposition.filename.Trim(“”);
filename=this.EnsureCorrectFilename(文件名);
使用(FileStream output=System.IO.File.Create(this.GetPathAndFilename(filename)))
等待source.CopyToAsync(输出);
}
返回这个.View();
}
私有字符串文件名(字符串文件名)
{
if(filename.Contains(“\\”)
filename=filename.Substring(filename.LastIndexOf(“\\”)+1);
返回文件名;
}
私有字符串GetPathAndFilename(字符串文件名)
{
返回this.hostingEnvironment.WebRootPath+“\\uploads\\”+文件名;
}
使用(.Net Core)的完整工作示例。部分答案采用了上述答案,并修复了编译错误
假设您想要上传文件,那么您将提交带有上传文件的表单
Register.cshtml
由于参数名称不同,正在获取null值。
客户端:
而不是将file-i add fromData设置为与动作方法参数名相同的
formData.append('formData' myfile.files[i]);
上载csv文件时,请添加验证以仅允许csv文件。
当你上传多个文件时 Html:添加多个属性
<input type="file" id="myfile" class="required" multiple />
服务器端:添加
公共异步任务上载文件(列表formData)
{
//在这里做点什么
}
如果您没有使用表单标记,那么添加@Html.AntiForgeryToken()现在有什么问题?您甚至有没有收到对您的操作方法的调用?服务器是否需要
数据:{formData:formData}
?在公共异步任务上载文件(formfile formData)中需要什么formData
?任务的目的是什么?@guest271314如果我将其与大括号一起使用,我会得到null@SaurabhTiwari我可以破坏该方法,但formData的值是null@jsonGPPD你能接受答案吗?我刚刚试过Mohammed Noureldin的答案,这对我有效,哪一个对你有效?内容类型如何et to media?@NevilleNazerane AFAIK jquery将自动为您的ajax请求设置适当的内容类型。我目前正在使用此设置在我的一个项目中上载excel文档。问题是,在Asp.Net Core中,没有HttpPostedFileBase,只有IFormFile。有什么方法可以实现该文件吗?@Jsongpd忘记了这一点。检查更新后的答案。工作正常。在我发送的示例模型中,还包含其他信息,如firstname last name等。公共类模型{public string firstname{get;set;}公共列表附件{get;set;}当我从ajax发送邮件时,我收到了400个状态码。如何发布?@SagarPatil请发布一个关于该问题的新问题,并在此处添加问题的链接作为评论,我将很高兴尽我最大的努力提供帮助。@MohammedNoureldin请在此处找到我的问题您在列出最佳选项方面的创造力。非常漂亮
[HttpPost]
public async Task<IActionResult> Index(IList<IFormFile> files)
{
foreach (IFormFile source in files)
{
string filename = ContentDispositionHeaderValue.Parse(source.ContentDisposition).FileName.Trim('"');
filename = this.EnsureCorrectFilename(filename);
using (FileStream output = System.IO.File.Create(this.GetPathAndFilename(filename)))
await source.CopyToAsync(output);
}
return this.View();
}
private string EnsureCorrectFilename(string filename)
{
if (filename.Contains("\\"))
filename = filename.Substring(filename.LastIndexOf("\\") + 1);
return filename;
}
private string GetPathAndFilename(string filename)
{
return this.hostingEnvironment.WebRootPath + "\\uploads\\" + filename;
}
@using UploadFileAjaxPostWebApp.Models.Account
@model RegisterModel
@using (Html.BeginForm("Register", "Account", FormMethod.Post))
{
<div>
<label>First Name </label>
<input type="text" name="FirstName" value="John" />
</div>
<div>
<label>Second Name </label>
<input type="text" name="SecondName" value="Smith" />
</div>
<div>
<label>Resume</label>
<input type="file" id="fileUpload1" onchange="uploadFiles('fileUpload1');" />
<input type="hidden" id="ResumeFileName" name="ResumeFileName" value="@Model.ResumeFileName" />
</div>
<div>
<input type="submit" value="Submit" />
</div>
}
<script type="text/javascript">
function uploadFiles(inputId) {
var input = document.getElementById(inputId);
var files = input.files;
var formData = new FormData();
for (var i = 0; i !== files.length; i++) {
formData.append("files", files[i]);
}
$.ajax(
{
url: "/account/uploadfiles",
data: formData,
processData: false,
contentType: false,
type: "POST",
success: function (data) {
// Set the property of the Model.
$("#ResumeFileName").val(data.fileName);
alert("Files Uploaded! " + data.fileName);
}
}
);
}
</script>
using System;
using System.Collections.Generic;
using System.IO;
using System.Threading.Tasks;
using Microsoft.AspNetCore.Mvc;
using UploadFileAjaxPostWebApp.Models.Account;
using Microsoft.AspNetCore.Hosting;
using Microsoft.AspNetCore.Http;
using Microsoft.Net.Http.Headers;
namespace UploadFileAjaxPostWebApp.Controllers
{
public class AccountController : Controller
{
private readonly IWebHostEnvironment _hostEnvironment;
public AccountController(IWebHostEnvironment hostEnvironment)
{
_hostEnvironment = hostEnvironment;
}
public IActionResult Register()
{
RegisterModel model = new RegisterModel();
return View(model);
}
[HttpPost]
public IActionResult Register(RegisterModel model)
{
// Handle your post action ....
return View(model);
}
[HttpPost]
public async Task<ActionResult> UploadFiles(IList<IFormFile> files)
{
string fileName = null;
foreach (IFormFile source in files)
{
// Get original file name to get the extension from it.
string orgFileName = ContentDispositionHeaderValue.Parse(source.ContentDisposition).FileName.Value;
// Create a new file name to avoid existing files on the server with the same names.
fileName = DateTime.Now.ToFileTime() + Path.GetExtension(orgFileName);
string fullPath = GetFullPathOfFile(fileName);
// Create the directory.
Directory.CreateDirectory(Directory.GetParent(fullPath).FullName);
// Save the file to the server.
await using FileStream output = System.IO.File.Create(fullPath);
await source.CopyToAsync(output);
}
var response = new { FileName = fileName };
return Ok(response);
}
private string GetFullPathOfFile(string fileName)
{
return $"{_hostEnvironment.WebRootPath}\\uploads\\{fileName}";
}
}
}
namespace UploadFileAjaxPostWebApp.Models.Account
{
public class RegisterModel
{
public string FirstName { get; set; }
public string SecondName { get; set; }
public string ResumeFileName { get; set; }
}
}
formData.append('formData' myfile.files[i]);
function uploadcsvfile() {
var myfile= document.getElementById("myfile");
var formData = new FormData();
if (myfile.value.toLowerCase().lastIndexOf(".csv") == -1)
{
alert("Please upload a file with .csv extension.");
return false;
}
// else code to upload
}
<input type="file" id="myfile" class="required" multiple />
public async Task<JsonResult> UploadFile(List<IFormFile> formData)
{
// do something here
}