Javascript 简化我的函数(循环、数组)?
我有一个重复了几次的函数,我相信可以简化并从数组发送变量Javascript 简化我的函数(循环、数组)?,javascript,jquery,arrays,function,loops,Javascript,Jquery,Arrays,Function,Loops,我有一个重复了几次的函数,我相信可以简化并从数组发送变量 var i = masterdata.timing.split(','); var index = 0; for (index = 0; index < i.length; ++index) { $("#timing_" + i[index].trim()).prop('checked', true); } var i = masterdata.con
var i = masterdata.timing.split(',');
var index = 0;
for (index = 0; index < i.length; ++index) {
$("#timing_" + i[index].trim()).prop('checked', true);
}
var i = masterdata.concern.split(',');
var index = 0;
for (index = 0; index < i.length; ++index) {
$("#concern_" + i[index].trim()).prop('checked', true);
}
var i = masterdata.steps.split(',');
var index = 0;
for (index = 0; index < i.length; ++index) {
$("#steps_" + i[index].trim()).prop('checked', true);
}
你的想法应该行得通:
var i;
var index = 0;
var j = 0;
var chkgroup = ['timing', 'concern', 'steps'];
var currentGroup;
for (j = 0; j < chkgroup.length; ++j) {
currentGroup = chkgroup[j];
i = masterdata[currentGroup].split(',');
for (index = 0; index < i.length; ++index) {
$("#" + currentGroup + "_" + i[index].trim())
.prop('checked', true);
}
}
请注意,中没有为…定义顺序,因此如果需要保证以特定顺序迭代对象属性,最好使用预定义数组
您还可以使用$来获得乐趣。map
:
var values = $.map(masterdata, function (i, currentGroup) {
return $.map(i.split(','), function (val) {
return $('#' + currentGroup + '_' + val.trim());
});
});
$(values).prop('checked', true);
var chkgroup=[‘计时’、‘关注’、‘步骤’];
setProps(chkgroup,masterdata);
函数setProps(c,m){
$。每个(c,功能(i,组){
VarI=m[组]分裂(',');
var指数=0;
对于(索引=0;索引
事实上,您的代码仍然有点嘈杂且不可读,即开发人员必须花费至少几分钟的时间对其进行分析,以了解逻辑是否正确。使用loDash或下划线,可以简化代码并将其转换为:
var selector = _.chain(masterdata)
//pick only needed items
.pick(masterdata, 'timing', 'concern', 'steps')
.map(function (item, key) {
//split and transform the string into selector, e.g. #timing_1
var ids = item.split(',');
var mapped = _.map(ids, function (id) { return "#" + key + "_" + id.trim(); });
return mapped.join();
})
.value()
.join();
$(selector).prop('checked', true);
和var i中的工作示例,masterdata.Timeing随类别而变化。@triplethreat77:已更新,请查看
var values = $.map(masterdata, function (i, currentGroup) {
return $.map(i.split(','), function (val) {
return $('#' + currentGroup + '_' + val.trim());
});
});
$(values).prop('checked', true);
var chkgroup = [ 'timing', 'concern', 'steps' ];
setProps( chkgroup, masterdata );
function setProps( c, m ) {
$.each(c, function(i, group) {
var i = m[group]split(',');
var index = 0;
for (index = 0; index < i.length; ++index) {
$("#" + group + "_" + i[index].trim()).prop('checked', true);
}
});
}
var selector = _.chain(masterdata)
//pick only needed items
.pick(masterdata, 'timing', 'concern', 'steps')
.map(function (item, key) {
//split and transform the string into selector, e.g. #timing_1
var ids = item.split(',');
var mapped = _.map(ids, function (id) { return "#" + key + "_" + id.trim(); });
return mapped.join();
})
.value()
.join();
$(selector).prop('checked', true);