Groovy JSON/GPath查询

给定以下JSON，我想提取邮政编码（长名称或短名称）。我曾使用JsonSlurper将其吸收到变量中，并尝试使用find/contains/etc进行各种查询，以获取在其“类型”中包含“邮政编码”但无法识别的节点。非常感谢您的帮助

{
   "results" : [
      {
         "address_components" : [
            {
               "long_name" : "Jefferson Ave",
               "short_name" : "Jefferson Ave",
               "types" : [ "route" ]
            },
            {
               "long_name" : "North Newport News",
               "short_name" : "North Newport News",
               "types" : [ "neighborhood", "political" ]
            },
            {
               "long_name" : "Newport News",
               "short_name" : "Newport News",
               "types" : [ "locality", "political" ]
            },
            {
               "long_name" : "Virginia",
               "short_name" : "VA",
               "types" : [ "administrative_area_level_1", "political" ]
            },
            {
               "long_name" : "United States",
               "short_name" : "US",
               "types" : [ "country", "political" ]
            },
            {
               "long_name" : "23608",
               "short_name" : "23608",
               "types" : [ "postal_code" ]
            }
         ],
         "formatted_address" : "Jefferson Ave & Denbigh Blvd, Newport News, VA 23608, USA",
         "geometry" : {
            "location" : {
               "lat" : 37.13852930,
               "lng" : -76.52013079999999
            },
            "location_type" : "APPROXIMATE",
            "viewport" : {
               "northeast" : {
                  "lat" : 37.13987828029151,
                  "lng" : -76.51878181970848
               },
               "southwest" : {
                  "lat" : 37.13718031970851,
                  "lng" : -76.52147978029149
               }
            }
         },
         "types" : [ "intersection" ]
      }
   ],
   "status" : "OK"
}

---

以下内容应找到具有邮政编码类型的节点。如果

结果

或

地址_组件

有多个列表项，则必须通过使用迭代替换索引访问来进行相应调整，但希望这会有所帮助

import groovy.json.*

def text = '''
{
   "results" : [
<omitted rest to save space>
....
}
'''

def json = new JsonSlurper().parseText(text)

def theNode = json.results[0]
                  .address_components
                  .find { it.types[0] == 'postal_code' }

assert '23608' == theNode.long_name

import groovy.json*
定义文本=“”
{
“结果”：[
....
}
'''
def json=new JsonSlurper（）.parseText（文本）
def theNode=json.results[0]
.address\u组件
.find{it.types[0]=“邮政编码”}
断言'23608'==node.long\u名称

@GaryWhite+1如果正如John所说，您有多个结果或邮政编码，那么这应该是可行的：

List codes=json.results.address\u components*.findAll{it.types}.flatte（）.long\u name