Loops 当python循环到达特定数字的范围时，如何停止它？

我是一名计算机科学的新生，在编码方面几乎没有经验，我遇到了一个路障

我们的任务是使用巴比伦算法找到用户输入的数字的平方根。巴比伦算法是（猜测+输入/猜测）/2。我正在使用一个循环，并用上一次迭代的答案替换“猜测”

我想做的是，一旦循环在真平方根的10倍^-15范围内，停止循环并打印答案

Repeat = True
while Repeat == True:
    og = float(input("What do you want to find the square root of?: "))
    print("Okay, we will use the Babylonian algorithm to find the square root of " + str(og) + ".")
    guess = float(input("Roughly estimate what the square root of " + str(og) + " is: "))
    print("Each answer will get closer to the true square root.")
    for answer in range(1,15):
        answer = ((guess + (og/guess))/2)
        print(answer)
        guess = (answer)
    else:
    print("The square root of " + str(og) + " is roughly " + str(answer) + ".")
    end = input("Do you want to find the square root of another number? y/n: ")
    if end == 'y':
            Repeat = True #This repeats the program
        else:
            Repeat = False #This ends the 'Repeat' loop. 
            print("Okay, thank you for using my program!")

---

目前，我需要重复一定的次数（15次）。但就像我说的，我不希望它重复一定的次数，而是希望它在一定程度上接近真实答案

你可以做一个while循环，直到达到你的ε。大概是这样的：

Repeat = True
while Repeat == True:
    og = float(input("What do you want to find the square root of?: "))
    print("Okay, we will use the Babylonian algorithm to find the square root of " + str(og) + ".")
    guess = float(input("Roughly estimate what the square root of " + str(og) + " is: "))
    print("Each answer will get closer to the true square root.")
    for answer in range(1,15):
        answer = ((guess + (og/guess))/2)
        print(answer)
        guess = (answer)
    else:
    print("The square root of " + str(og) + " is roughly " + str(answer) + ".")
    end = input("Do you want to find the square root of another number? y/n: ")
    if end == 'y':
            Repeat = True #This repeats the program
        else:
            Repeat = False #This ends the 'Repeat' loop. 
            print("Okay, thank you for using my program!")

while closeness > epsilon:
   answer = ((guess + (og/guess))/2)
   answer_squared = answer * answer
   closeness = answer_squared - og
   guess = (answer)

与此相反：

for answer in range(1,15):
    answer = ((guess + (og/guess))/2)
    print(answer)
    guess = (answer)

您可以执行while循环：

import math
real_answer=math.sqrt(og)
while abs(real_answer-guess)<=x: #x is how close you want your guess to be to the real answer
    guess=(guess+(og/guess))/2
    print(guess)

导入数学
real_answer=math.sqrt（og）
而abs（真实答案猜测）