Matlab 旋转图像-不同程度
我正在尝试自己的旋转图像算法,而不使用imrotateMatlab 旋转图像-不同程度,matlab,image-processing,computer-vision,Matlab,Image Processing,Computer Vision,我正在尝试自己的旋转图像算法,而不使用imrotate clear all img1 = imread('image1.jpg');imshow(img1); [m,n,p]=size(img1); thet = pi/6; m1=round(m*1.5); n1=round(n*1.5); rotatedImg = zeros(m1,n1); for i=1:m for j=1:n t = uint16((i)*cos(thet)-(j)*sin(thet)+m+
clear all
img1 = imread('image1.jpg');imshow(img1);
[m,n,p]=size(img1);
thet = pi/6;
m1=round(m*1.5);
n1=round(n*1.5);
rotatedImg = zeros(m1,n1);
for i=1:m
for j=1:n
t = uint16((i)*cos(thet)-(j)*sin(thet)+m+100);
s = uint16((i)*sin(thet)+(j)*cos(thet));
if i>0 && j>0 && i<=m && j<=n
try rotatedImg(t,s,1)=img1(i,j,1);
catch
a=1;
end
end
end
end
figure;
imshow(rotatedImg);
全部清除
img1=imread('image1.jpg');imshow(img1);
[m,n,p]=尺寸(img1);
t=pi/6;
m1=圆形(m*1.5);
n1=圆形(n*1.5);
rotatedImg=零(m1,n1);
对于i=1:m
对于j=1:n
t=uint16((i)*cos(thet)-(j)*sin(thet)+m+100);
s=uint16((i)*sin(thet)+(j)*cos(thet));
如果i>0&&j>0&&i那么,有两个问题:
始终围绕原点旋转。这就是您需要调整每个角度的偏移(100)的原因。更好的解决方案是围绕图像中心旋转
你没有做任何插值。虽然这本身不是原因,但由于舍入错误,可能会出现目标图像中的每个像素都未命中的情况。最好遍历目标图像并从源图像中获取正确的像素
以下是我的解决方案:
clear all
img1 = imread('ngc6543a.jpg');
imshow(img1);
[m,n,p]=size(img1);
thet = pi/6;
m1=round(m*1.5);
n1=round(n*1.5);
rotatedImg = zeros(m1,n1, 3, 'uint8');
tic
for i=1:m1
for j=1:n1
p = [i; j] - [m1/2; n1/2];
source = [cos(thet), sin(thet); -sin(thet), cos(thet)] * p;
source = source + [m/2; n/2];
t = int16(source(1));
s = int16(source(2));
if t>0 && s>0 && t<=m && s<=n
rotatedImg(i,j,:) = img1(t,s,:);
end
end
end
toc
figure;
imshow(rotatedImg);
全部清除
img1=imread('ngc6543a.jpg');
imshow(img1);
[m,n,p]=尺寸(img1);
t=pi/6;
m1=圆形(m*1.5);
n1=圆形(n*1.5);
rotatedImg=零(m1,n1,3,'uint8');
抽搐
对于i=1:m1
对于j=1:n1
p=[i;j]-[m1/2;n1/2];
source=[cos(thet),sin(thet);-sin(thet),cos(thet)]*p;
震源=震源+[m/2;n/2];
t=int16(源(1));
s=int16(源(2));
如果t>0&&s>0&&tI尝试使用此图像()解决方案,但由于某种原因,图像的顶部和底部被剪裁。我尝试使用这些角度-pi/2,((pi/6)*4)-输出图像被剪裁,并添加适当的边界计算。请注意循环中已更改的索引。非常感谢您的帮助。我想知道你是否可以解释一下,如果上面的不是双线性插值,你使用了什么方法?这可能被称为“最近邻”。使用双线性,您不应该将坐标转换为int16,而是从所有四个相邻像素中获得一些颜色。
clear all
img1 = imread('kDdx5.jpg');
imshow(img1);
[orgHeight,orgWidth,p]=size(img1);
thet = pi/7;
matrix = [cos(thet), -sin(thet); sin(thet), cos(thet)];
p1 = abs(matrix * [orgWidth/2; orgHeight/2]);
p2 = abs(matrix * [orgWidth/2; -orgHeight/2]);
corner = [max(p1(1), p2(1)); max(p1(2), p2(2))];
newWidth = ceil(2*corner(1));
newHeight = ceil(2*corner(2));
rotatedImg = zeros(newHeight, newWidth, 3, 'uint8');
tic
for i=1:newWidth
for j=1:newHeight
p = [i; j] - [newWidth/2; newHeight/2];
source = matrix * p;
source = source + [orgWidth/2; orgHeight/2;];
t = int16(source(1));
s = int16(source(2));
if t>0 && s>0 && s<=orgHeight && t<=orgWidth
rotatedImg(j,i,:) = img1(s,t,:);
end
end
end
toc
figure;
imshow(rotatedImg);