SQL数据透视和计算以字符串形式存储的日期之间的差异-MySQL

SQL数据透视和计算以字符串形式存储的日期之间的差异-MySQL,mysql,sql,pivot,mariadb,Mysql,Sql,Pivot,Mariadb,我有两张桌子。第一个称为posts,第二个称为postmeta。(如果有人注意到,我正在使用Wordpress db,这对于这项任务来说并不重要) posts表如下所示(为此缩短) postETA表如下所示。日期格式为d.m.Y.G:i:s meta_id | post_id | meta_key | meta_value ------------------------------------------ 1 | 1 | from | 1.1.2017. 10:

我有两张桌子。第一个称为
posts
,第二个称为
postmeta
。(如果有人注意到,我正在使用Wordpress db,这对于这项任务来说并不重要)

posts
表如下所示(为此缩短)

postETA
表如下所示。日期格式为d.m.Y.G:i:s

meta_id | post_id | meta_key | meta_value
------------------------------------------
1       | 1       | from     | 1.1.2017. 10:00:00
2       | 1       | to       | 1.1.2017. 16:00:00
3       | 2       | from     | 2.1.2017. 12:00:00
4       | 2       | to       | 2.1.2017. 15:00:00
在那些表中,
ID
=
post\u ID
。 想要得到的结果是下表中的
date\u diff
from
to
之间的差异,必须通过SQL计算(date\u diff=to-from)。请注意,
meta_key
被定义为
VARCHAR
meta_value
被定义为
LONGTEXT
,这使得计算更加困难

ID | title | from               | to                 | date_diff
------------------------------------------------------------------
1  | 1     | 1.1.2017. 10:00:00 | 1.1.2017. 16:00:00 | 6
2  | 1     | 2.1.2017. 12:00:00 | 2.1.2017. 15:00:00 | 3
这是我现在的代码。让行变成列对我来说有点问题,而且计算更麻烦

SELECT posts.ID, posts.post_title, postmeta.meta_key, postmeta.meta_value 
FROM posts
INNER JOIN postmeta 
ON posts.ID = postmeta.post_id
WHERE post_status = 'publish' 
AND post_type = 'hours' 
AND (postmeta.meta_key = 'from' OR postmeta.meta_key = 'to');

非常感谢。:)

您可以在POSTETA上使用自连接来获取两个分离的列 使用str_to_date转换日期中的字符串 对保留字(例如:from)使用适当的backtics 和TIMESTAMPDIFF,用于获取diff的小时数

  SELECT 
          posts.ID
        , posts.post_title
        , str_to_date(table_from.meta_value, '%d.%m.%Y. %H:%i:%s')  as `from` 
        , str_to_date(table_to.meta_value, '%d.%m.%Y. %H:%i:%s' ) as `to` 
        , TIMESTAMPDIFF(HOUR, str_to_date(table_from.meta_value, '%d.%m.%Y. %H:%i:%s') , 
                                    str_to_date(table_to.meta_value, '%d.%m.%Y. %H:%i:%s' )) as diff
  FROM posts
  INNER JOIN postmeta table_from ON posts.ID = table_from.post_id and table_from.meta_key ='from'
  inner join postmeta table_to ON posts.ID = table_to.post_id and table_to.meta_key ='to'
  WHERE post_status = 'publish' 
  AND post_type = 'hours' 
对于十进制,您可以使用


timestampdiff(分钟、开始日期、结束日期)/60作为diff,我希望它能有所帮助

SELECT 
   p.id, 
   p.post_title, 
   postmeta_temp.from, 
   postmeta_temp.to, 
   postmeta_temp.date_diff 
FROM   posts p 
   INNER JOIN (SELECT postmeta_from.post_id 
                      AS post_id, 
                      postmeta_from.meta_key 
                                     AS from, 
                      postmeta_to.meta_key 
                                     AS to, 
                      Date_diff(postmeta_to.meta_value, 
                      postmeta_from.meta_value) 
                                     AS date_diff 
               FROM   postmeta postmeta_from 

                      INNER JOIN postmeta postmeta_to 

                              ON postmeta_from.post_id = postmeta_to.post_id 

                                 AND postmeta_from.meta_key = 'from' 

                                 AND postmeta_to.meta_key = 'to') AS 

              postmeta_temp 

           ON p.id = postmeta_temp.post_id 
例如(比斯盖里奇的方法慢,但更容易阅读…)


我把最后一部分留给读者作为一个(简单的)练习。

对于每一个ID,我下次会用相同的ID和下一个日期检查

select pm.post_id as ID, pm.post_id as title, pm.metavalue as from,  
(select x.metavalue from postmeta x where x.enter code herepost_id = pm.post_id and not x.meta_key = 'from') 
as to , 
(select cast(x.metavalue as timestamp) - cast(pm.metavalue as timestamp) from postmeta x 
      where x.post_id = pm.post_id and not x.meta_key = 'from') as date_diff from 
postmeta pm where pm.meta_key = 'from';


 id | title |        from        |         to         | date_diff 
----+-------+--------------------+--------------------+-----------
  1 |     1 | 1.1.2017. 10:00:00 | 1.1.2017. 16:00:00 | 06:00:00
  2 |     2 | 2.1.2017. 12:00:00 | 2.1.2017. 15:00:00 | 03:00:00

感谢您的回复,我尝试了代码,但是from、to和diff只有空值。在测试代码时,我注意到str_to_date返回空值,所以这可能是原因,但仍然不起作用,但是,它非常接近。可能是日期格式。。。年复一年地漏掉一点。。答案用点更新。如果使用24小时,格式必须为H而不是H。。回答UpdateEdit起作用,TIMESTAMPDIFF是否可以以小数形式显示小时,例如1.5小时,因为目前它只显示整小时我认为你的数据集出错了。什么是post_id=3!?!哦,对不起,错别字,是2:)草莓,谢谢你的回答,太棒了,不幸的是我只能把一个答案当作正确答案。你努力回答,所以我能做的最小的事情就是给它投票;)谢谢:)
DROP TABLE IF EXISTS posts;

CREATE TABLE posts
(id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,post_title VARCHAR(12) NOT NULL
,post_status VARCHAR(12) NOT NULL
,post_type VARCHAR(12) NOT NULL
);

INSERT INTO posts VALUES
(1,'One','publish','hours'),
(2,'Two','publish','hours');

DROP TABLE IF EXISTS postmeta;

CREATE TABLE postmeta
(meta_id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,post_id INT NOT NULL
,meta_key VARCHAR(12) NOT NULL
,meta_value VARCHAR(20) NOT NULL
);

INSERT INTO postmeta VALUES
(1,1,'from','1.1.2017. 10:00:00'),
(2,1,'to'  ,'1.1.2017. 16:00:00'),
(3,2,'from','2.1.2017. 12:00:00'),
(4,2,'to'  ,'2.1.2017. 15:00:00');

-- Date format is d.m.Y. H:i:s.

SELECT post_id
     , MAX(CASE WHEN meta_key = 'from' THEN STR_TO_DATE(meta_value,'%d.%m.%Y. %H:%i:%s') END) `from`
     , MAX(CASE WHEN meta_key = 'to' THEN STR_TO_DATE(meta_value,'%d.%m.%Y. %H:%i:%s') END) `to`
     , TIMEDIFF(
           MAX(CASE WHEN meta_key = 'to' THEN STR_TO_DATE(meta_value,'%d.%m.%Y. %H:%i:%s') END)
         , MAX(CASE WHEN meta_key = 'from' THEN STR_TO_DATE(meta_value,'%d.%m.%Y. %H:%i:%s') END)
               ) date_diff
  FROM postmeta 
 GROUP 
    BY post_id;

+---------+---------------------+---------------------+-----------+
| post_id | from                | to                  | date_diff |
+---------+---------------------+---------------------+-----------+
|       1 | 2017-01-01 10:00:00 | 2017-01-01 16:00:00 | 06:00:00  |
|       2 | 2017-01-02 12:00:00 | 2017-01-02 15:00:00 | 03:00:00  |
+---------+---------------------+---------------------+-----------+
select pm.post_id as ID, pm.post_id as title, pm.metavalue as from,  
(select x.metavalue from postmeta x where x.enter code herepost_id = pm.post_id and not x.meta_key = 'from') 
as to , 
(select cast(x.metavalue as timestamp) - cast(pm.metavalue as timestamp) from postmeta x 
      where x.post_id = pm.post_id and not x.meta_key = 'from') as date_diff from 
postmeta pm where pm.meta_key = 'from';


 id | title |        from        |         to         | date_diff 
----+-------+--------------------+--------------------+-----------
  1 |     1 | 1.1.2017. 10:00:00 | 1.1.2017. 16:00:00 | 06:00:00
  2 |     2 | 2.1.2017. 12:00:00 | 2.1.2017. 15:00:00 | 03:00:00