Mysql orderBy不使用as关键字laravel

我正在使用laravel并构建一个查询，但orderby不使用select中的generate字段

$slots = Slot::select(\DB::raw('STR_TO_DATE(slots.when, "%h:%i %p") as timestart,id, `when`, end, namePanel, nameNetwork, nameAngel101, nameAngel102, nameAngel103, locationPanel, locationNetwork, locationAngel101, locationAngel102, locationAngel103, day_id, moderator_id, created_at, updated_at'))->where('day_id',$day['id'])->orderBy('timestart','ASC')->get();

结果未使用timestart排序，已尝试打印->toSql（），它在phpmyadmin中看起来很好，运行也很好

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有什么想法吗？

你可以用这个。。我想这对你有帮助。如下所示

    $slots = Slot::select(\DB::raw('STR_TO_DATE(slots.when, "%h:%i %p") as timestart,id, `when`, end, namePanel, nameNetwork, nameAngel101, nameAngel102, nameAngel103, locationPanel, locationNetwork, locationAngel101, locationAngel102, locationAngel103, day_id, moderator_id, created_at, updated_at'))->orderBy('timestart','ASC')->where('day_id',$day['id'])->get();

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你可以用这个。。我想这对你有帮助。如下所示

    $slots = Slot::select(\DB::raw('STR_TO_DATE(slots.when, "%h:%i %p") as timestart,id, `when`, end, namePanel, nameNetwork, nameAngel101, nameAngel102, nameAngel103, locationPanel, locationNetwork, locationAngel101, locationAngel102, locationAngel103, day_id, moderator_id, created_at, updated_at'))->orderBy('timestart','ASC')->where('day_id',$day['id'])->get();

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您看到了什么类型的错误？不是错误，但结果根本不按timestart排序您是否按id而不是timestart检查它？使用除timestart之外的任何列timestart的数据类型是什么？您看到了什么类型的错误？不是错误，但结果根本不按timestart排序您是否按id而不是timestart检查它timestart？使用除timestart之外的任何列timestart的数据类型是什么？这是相同的内容这是相同的内容