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在sqlplus/Oracle中将历元转换为日期_Oracle_Datetime_Date_Sqlplus_Epoch - Fatal编程技术网

在sqlplus/Oracle中将历元转换为日期

在sqlplus/Oracle中将历元转换为日期,oracle,datetime,date,sqlplus,epoch,Oracle,Datetime,Date,Sqlplus,Epoch,我有下表: SQL> desc recording Name Null? Type -------------------- -------- ------ CAPTUREID NOT NULL NUMBER(9) STARTDATE NOT NULL DATE ENDDATE DATE STATE NUM

我有下表:

SQL> desc recording
 Name                 Null?    Type
 -------------------- -------- ------
 CAPTUREID            NOT NULL NUMBER(9)
 STARTDATE            NOT NULL DATE
 ENDDATE                       DATE
 STATE                         NUMBER(1)
 ESTIMATEDENDTIME              NUMBER(13)
这张表只有一行:

SQL> select * from recording where CAPTUREID=14760457;

 CAPTUREID STARTDATE           ENDDATE             STATE ESTIMATEDENDTIME
---------- ------------------- ------------------- ----- ----------------
  14760457 29/09/2010 08:50:01 29/09/2010 09:52:04     0    1285746720000
我很确定这之前已经被问过很多次了,但是我找到的所有解决方案都没有真正起作用,所以。。。如何在SQLPLUS中的单个查询中将
ESTIMATEDENDTIME
从原始历元格式转换为
DD/MM/yyyy HH:MI:SS
格式


谢谢

在Oracle中,向日期添加X将在X天后返回日期

若EstimatedTime是从Epoch开始的毫秒,那个么您可以

DATE '1970-01-01' + ( 1 / 24 / 60 / 60 / 1000) * ESTIMATEDENDTIME
然后使用to_char实现结果日期的正确格式。e、 g:

SELECT 
  captureid
, startdate
, enddate
, state
, estimatedendtime
, DATE '1970-01-01' + ( 1 / 24 / 60 / 60 / 1000) * estimatedendtime AS estimatedenddate
FROM recording

该死!这比我尝试的其他解决方案更快更简单!谢谢!
select ((timestamp_coloum_name - to_date('01-JAN-1970','DD-MON-YYYY')) * (86400)) from any_table;