Php &引用;缺少RequiredParameter“;与YouTube API交互时出错
当我使用YouTube API(v3)的curl方法时 它表明Php &引用;缺少RequiredParameter“;与YouTube API交互时出错,php,curl,youtube-api,Php,Curl,Youtube Api,当我使用YouTube API(v3)的curl方法时 它表明 Array ( [error] => Array ( [errors] => Array ( [0] => Array ( [domain] => youtube.parameter [reason] => missingRequiredParameter
Array (
[error] => Array (
[errors] => Array (
[0] => Array (
[domain] => youtube.parameter
[reason] => missingRequiredParameter
[message] => No filter selected.
[locationType] => parameter
[location] =>
)
)
[code] => 400
[message] => No filter selected.
)
)
出现此错误的原因?您应该能够为用户名指定
。你确定$\u GET['username']
不是空的吗?当你打印$url
时,你得到了什么?你应该能够只为username
指定。你确定$\u GET['username']
不是空的吗?当你打印$url
时,你得到了什么?
Array (
[error] => Array (
[errors] => Array (
[0] => Array (
[domain] => youtube.parameter
[reason] => missingRequiredParameter
[message] => No filter selected.
[locationType] => parameter
[location] =>
)
)
[code] => 400
[message] => No filter selected.
)
)