Php &引用;缺少RequiredParameter“;与YouTube API交互时出错

Php &引用;缺少RequiredParameter“;与YouTube API交互时出错,php,curl,youtube-api,Php,Curl,Youtube Api,当我使用YouTube API(v3)的curl方法时 它表明 Array ( [error] => Array ( [errors] => Array ( [0] => Array ( [domain] => youtube.parameter [reason] => missingRequiredParameter

当我使用YouTube API(v3)的curl方法时

它表明

Array ( 
    [error] => Array (
        [errors] => Array (
            [0] => Array (
                [domain] => youtube.parameter 
                [reason] => missingRequiredParameter 
                [message] => No filter selected. 
                [locationType] => parameter 
                [location] => 
            ) 
        )
        [code] => 400 
        [message] => No filter selected. 
    ) 
)

出现此错误的原因?

您应该能够为用户名指定
。你确定
$\u GET['username']
不是空的吗?当你打印
$url
时,你得到了什么?你应该能够只为username
指定
。你确定
$\u GET['username']
不是空的吗?当你打印
$url
时,你得到了什么?
Array ( 
    [error] => Array (
        [errors] => Array (
            [0] => Array (
                [domain] => youtube.parameter 
                [reason] => missingRequiredParameter 
                [message] => No filter selected. 
                [locationType] => parameter 
                [location] => 
            ) 
        )
        [code] => 400 
        [message] => No filter selected. 
    ) 
)