Php Symfony：不同环境下的自定义侦听器更改响应

我做了如下的听众：

namespace AppBundle\EventListener;

use Symfony\Component\HttpKernel\Event\GetResponseForExceptionEvent;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpKernel\Exception\HttpExceptionInterface;

class ExceptionListener
{
    public function onKernelException(GetResponseForExceptionEvent $event)
    {
        // You get the exception object from the received event
        $exception = $event->getException();
        $message = array(
            'message'=>$exception->getMessage(),
            'code'=>$exception->getCode(),
            'stacktrace'=>$exception->getTrace()
        );

        // Customize your response object to display the exception details
        $response = new Response();
        $response->setContent(json_encode($message,JSON_PRETTY_PRINT));

        // HttpExceptionInterface is a special type of exception that
        // holds status code and header details
        if ($exception instanceof HttpExceptionInterface) {
            $response->setStatusCode($exception->getStatusCode());
            $response->headers->replace($exception->getHeaders());
        } else {
            $response->setStatusCode(Response::HTTP_INTERNAL_SERVER_ERROR);
            $response->headers->set('content/type','application/json');
        }

        // Send the modified response object to the event
        $event->setResponse($response);
    }
}

当根据my

services.yml发生异常时，将触发上面的侦听器：

parameters:
services:
 app.exception_listener:
  class: AppBundle\EventListener\ExceptionListener
  tags:
   - { name: kernel.event_listener, event: kernel.exception }

现在我想实现的是，在生产环境中显示来自其他环境的不同json输出。我的意思是，最终用户/api消费者看到stacktrace是不明智的，也是个好主意

那么，您知道我在生产环境和开发环境中时如何知道吗？
您只需将
内核.environment
参数传递给您的类构造函数：

 app.exception_listener:
  class: AppBundle\EventListener\ExceptionListener
  arguments: ["%kernel.environment%"]
  tags:
   - { name: kernel.event_listener, event: kernel.exception }

然后在你的课堂上：

class ExceptionListener
{
    private $env;

    public function __construct($env)
    {
        $this->env = $env;
    }

    public function onKernelException(GetResponseForExceptionEvent $event)
    {
        if ($this->env == 'dev') {
            // do something
        } else {
            // do something else
        }
    }
}

您只需将
kernel.environment
参数传递给类构造函数：

 app.exception_listener:
  class: AppBundle\EventListener\ExceptionListener
  arguments: ["%kernel.environment%"]
  tags:
   - { name: kernel.event_listener, event: kernel.exception }

然后在你的课堂上：

class ExceptionListener
{
    private $env;

    public function __construct($env)
    {
        $this->env = $env;
    }

    public function onKernelException(GetResponseForExceptionEvent $event)
    {
        if ($this->env == 'dev') {
            // do something
        } else {
            // do something else
        }
    }
}