Php 如果另一个属性不是空的,则Symfony验证该属性
我有课Php 如果另一个属性不是空的,则Symfony验证该属性,php,validation,symfony,Php,Validation,Symfony,我有课 Class SubjectSegment{ /** *@CustomAssert\MyCitizenshipNumber() */ private $citizenshipNumber; /** *@CustomAssert\MyDate() */ private $citizenshipNumberIssuedDate; } 我真正想做的是有效的citizenshipNumber如果citizenshipNumber存在 实现这一目标的最佳方法是什么 您可以通
Class SubjectSegment{
/**
*@CustomAssert\MyCitizenshipNumber()
*/
private $citizenshipNumber;
/**
*@CustomAssert\MyDate()
*/
private $citizenshipNumberIssuedDate;
}
我真正想做的是有效的citizenshipNumber如果citizenshipNumber存在
实现这一目标的最佳方法是什么
您可以通过两种方式对此进行归档: 1) 回调验证器(由类方法验证) 2) 带着 我建议使用第二种方法,因此您必须将验证器配置/设置为类作用域,如:
/**
* @Annotation
*/
class MyCitizenshipNumber extends Constraint {
...
public function getTargets()
{
return self::CLASS_CONSTRAINT;
}
}
因此,您可以访问所有类字段成员
记住将验证器放在类定义的顶部,如:
/**
*@CustomAssert\MyCitizenshipNumber()
*/
Class SubjectSegment{
private $citizenshipNumber;
/**
*@CustomAssert\MyDate()
*/
private $citizenshipNumberIssuedDate;
}
希望这有帮助
Class SubjectSegment{
/**
*@CustomAssert\MyCitizenshipNumber()
*/
private $citizenshipNumber;
/**
*@CustomAssert\MyDate(group={"is_my_citizenship_number"})
*/
private $citizenshipNumberIssuedDate;
public function getGroupSequence(){
$sequence = ['SubjectSegment'];
if(null != $this->CitizenshipNumber){
$sequence[] = 'is_my_citizenship_number';
}
return $sequence;
}
}
验证器:
$violations = $container->get('validator')->validate($segment = new SubjectSegmet(), null,$segment->getGroupSequence() );
我需要的是,只有当citizenshipNumber不为空时才调用Constiaint MyDate。。类约束验证器。是否要在citizenshipNumber验证器中调用日期验证器?如果是这样,请看一看。如果这是您的解决方案,您可能必须在citizenshipNumber验证器中插入
验证器
组件。我真正需要的是转义@CustomAssert\MyDate when(null==$this->citizenshipNumber)。我使用的是symfony 2.6你对问题的评论回复如果(null===$this->citizenshipNumber&&null===$this->citizenshipNumberseSueddate){//put$context->addViolation…}
在这两种情况下如果(null====$this->citizenshipNumber)和如果(null!=$this->citizenshipNumber){}@CustomAssert\MyDate()正在验证。是否有任何方法可以使用@Assert\Expression{this.citizenshipNumber!=null,@Assert\MyDate()}。。。如果我们在symfony 2中有这样的功能,那就太好了。因此,请删除您的/**@CustomAssert\MyDate()*/
,并在自定义Assert类的isCitizenDateValid
方法中添加验证。如果symfony在表达式中引入Assert,那就太好了。。代码将是自解释的。
$violations = $container->get('validator')->validate($segment = new SubjectSegmet(), null,$segment->getGroupSequence() );