如何使用PHP将多个数组合并为单个数组

我从数据库中查询地址列，并将多个地址传递给Google Geocoder API，然后将纬度和经度结果存储在

$coordinate

变量中。当i

var\u导出（$coordinate）时我以以下格式获得输出：

'[19.0759837,72.8776559]''[47.6062095,-122.3320708]''[12.9715987,77.5945627]'

但在使用
print_r（数组（$variablename））时我以以下格式获取输出：

Array
(
 [0] => [19.0759837,72.8776559]
)
Array
(
  [0] => [47.6062095,-122.3320708]
)
Array
(
  [0] => [12.9715987,77.5945627]
)

但我希望输出是在单个数组中，类似这样

Array
(
 [0] => [19.0759837,72.8776559],
 [1] => [47.6062095,-122.3320708],
 [2] => [12.9715987,77.5945627]
)

这是php代码：

<?php 
    // database connection code and query to fetch address column the database and pass address to geocode()
header("content-type: application/json");
        header('Access-Control-Allow-Origin: *');
        $config = parse_ini_file('./config.ini');
        $connect = mysqli_connect('localhost',$config['username'],$config['password'],$config['dbname']);
        if (mysqli_connect_errno())
                {
                  echo "Failed to connect to MySQL: " . mysqli_connect_error();
                }
                $ordertracker = mysqli_query($connect, "select address from ordertracker");

                if (!$ordertracker)
                {
                    echo "Error fetching results: " . mysqli_error();

                }

        $address=array();
        while($row = mysqli_fetch_assoc($ordertracker)) {
             $address= $row['address'];
              geocode($address);  
        }
    function geocode($address)
     {
                $address = urlencode($address);
                $url = "http://maps.googleapis.com/maps/api/geocode/json?address=$address&sensor=false";
                $geocode=file_get_contents($url);
                $output= json_decode($geocode);
                $lat = $output->results[0]->geometry->location->lat;
                $long = $output->results[0]->geometry->location->lng;
                $coordinate = "[" . $lat . "," . $long . "]";  
                var_export($coordinate);  
      }
    ?>

如果您想要一个数组，那么不应该使用字符串文本和连接来构建它，因为这将导致一个字符串

相反，让函数生成一个包含两个值（纬度和经度）的数组，并将这些对附加到主循环中的主数组中：

$address = [];
while($row = mysqli_fetch_assoc($ordertracker)) {
    $address[] = geocode($row['address']);
}
print_r($address);

function geocode($address) {
    $address = urlencode($address);
    $url = "http://maps.googleapis.com/maps/api/geocode/json?address=$address&sensor=false";
    $geocode = file_get_contents($url);
    $output= json_decode($geocode);
    $lat = $output->results[0]->geometry->location->lat;
    $long = $output->results[0]->geometry->location->lng;
    $coordinate = [$lat, $long];  
    return $coordinate;
}

我很困惑。
$coordinate
是同时保持一个坐标还是三个坐标？如果有，你怎么取下一个？在一个循环中？$坐标变量保存所有三个变量，并且它将动态增长。
print\r（数组（您的字符串））
给出了
数组（[0]=>[19.0759837,72.8776559][47.6062095，-122.3320708][12.9715987,77.5945627]）
@Gauravkb那么，它是字符串吗？你能用
var\u export
而不是
echo
和
print\u r
重写问题中的示例吗？@Siguza当我使用var\u export（$coordinate）；我得到如下输出：
“[19.0759837,72.8776559]”[47.6062095，-122.3320708]”[12.9715987,77.5945627]”