Php 使用包含5个表的limit提取单个数据

因此，我有5个表，其中它与外键相互连接

下面是表3的输出示例

在表3中，我想做的是提取userid为10的user的SubdeptID，但在本例中，它有2个userid10，所以它同时打印这两个。我要打印的只是带有后一个TransferID的。我的选择声明如下

$sql_exp = "SELECT  a.UserID, b.Employeename, c.TransferID, e.Department
FROM    dbo.FA_Laptop a
        INNER JOIN dbo.users b
        on a.UserID = b.UserID
        INNER JOIN dbo.SubDeptTransfer c
            ON a.UserID = c.UserID  
        INNER JOIN dbo.SubDept d
            ON c.SudDeptID = d.SubDeptID
        INNER JOIN dbo.departments e
            ON d.DeptID = e.DeptID
WHERE  a.FAID = '$faidf' ORDER by c.TransferID DESC LIMIT 1"; 

我的php代码是

$rs = $conn->Execute($sql_exp);      
    if ($rs->EOF) {
    echo "<tr><td>Please check for the Employee Name or the Department</td>";
} else {
    while (!$rs->EOF){ 
    echo "<tr><td>".$rs->Fields("Department")." / ".$rs->Fields("EmployeeName")."</td>";
    $rs->movenext();
    }
       $rs->Close();  
}   

$rs=$conn->Execute（$sql\u exp）；
如果（$rs->EOF）{
echo“请检查员工姓名或部门”；
}否则{
而（！$rs->EOF）{
回显“$rs->字段（“部门”）。/”$rs->字段（“员工姓名”）；
$rs->movenext（）；
}
$rs->Close（）；
}   

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我在“限制”查询中出错。

MSSQL没有限制关键字

用限制代替

$sql_exp = "SELECT TOP 1 a.UserID, b.Employeename, c.TransferID, e.Department
FROM    dbo.FA_Laptop a
        INNER JOIN dbo.users b
        on a.UserID = b.UserID
        INNER JOIN dbo.SubDeptTransfer c
            ON a.UserID = c.UserID  
        INNER JOIN dbo.SubDept d
            ON c.SudDeptID = d.SubDeptID
        INNER JOIN dbo.departments e
            ON d.DeptID = e.DeptID
WHERE  a.FAID = '$faidf' ORDER by c.TransferID DESC"; 

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错误是什么？您使用了什么rdbms？mysql或mssql？mssql错误是“限制附近的语法不正确”