Php 数据库查询retuyrns字段按一种顺序显示，我想按另一种顺序显示它们

这可能已经得到了回答（或者应该是基础知识），所以请原谅noob的问题

我正在使用WP user_元数据库来存储用户的高级属性

数据按此顺序存储（这是userid=15的全部内容）：

以下是相关的PHP代码：

 $my_exportlist = $wpdb->get_results("SELECT `user_id` FROM `wp_m_membership_relationships` WHERE `level_id` = '2' ");
foreach ($my_exportlist as $duser) {

$my_stationinfo = $wpdb->get_results("SELECT * FROM `wp_usermeta` WHERE `meta_key` IN ('name', 'city', 'state', 'office') AND user_id ='$duser->user_id'");

foreach ($my_stationinfo as $myinfo) {
    $csv_output .= $myinfo->meta_value . ",";
    }
$csv_output .= "\n";
}

在第一次回答之后，我这样做了：

$my_stationinfo = $wpdb->get_results("GROUP_CONCAT(meta_value) val_output
        FROM `wp_usermeta`
        WHERE `meta_key` IN ('name', 'city', 'state', 'office') AND user_id ='$duser->user_id'
        ORDER BY FIELD(meta_key, 'name', 'city', 'state', 'office'");

我收到这个错误消息

WordPress database error: [You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'GROUP_CONCAT(meta_value) val_output FROM `wp_usermeta` WHERE `meta_key' at line 1]

在看了大量q/a和链接的mySQL说明之后，我仍然感到困惑

进一步的后续行动： 这是当前代码

   $my_exportlist = $wpdb->get_results("SELECT `user_id` FROM `wp_m_membership_relationships` WHERE `level_id` = '2' ");
foreach ($my_exportlist as $duser) {

$my_stationinfo = $wpdb->get_results(
    "SELECT GROUP_CONCAT(meta_value) val_output
        FROM   wp_usermeta 
        WHERE  meta_key IN ('primary_calls', 'city', 'state', 'office', 'contact_emerg', 'contact_routine', 'contact_backup', 'contact_billing', 'contact_eng', 'contact_web', 'contact_prod', 'contact_traffic') AND
               user_id = '$duser->user_id'
               ORDER BY FIELD(meta_key, 'primary_calls', 'city', 'primary_calls','state', 'office', 'contact_emerg', 'contact_routine', 'contact_backup', 'contact_billing', 'contact_eng', 'contact_web', 'contact_prod', 'contact_traffic')");
print_r($my_stationinfo);
var_dump($my_stationinfo);
echo $my_stationinfo->val_output[0] ;


foreach ($my_stationinfo as $myinfo) {

    $csv_output .= $myinfo;
}
$csv_output .= "\n";

结果是：

Array ( [0] => stdClass Object ( [val_output] => Altoona,PA,814.943.8112,WRTA ) )


array
  0 => 
    object(stdClass)[5]
      public 'val_output' => string 'Altoona,PA,814.943.8112,WRTA' (length=28)


Notice: Trying to get property of non-object in D:\Users\Dev\Documents\Websites\contract.dev\wp-content\plugins\custom_plugin\index_page.php on line 40

Catchable fatal error: Object of class stdClass could not be converted to string in D:\Users\Dev\Documents\Websites\contract.dev\wp-content\plugins\custom_plugin\index_page.php on line 45

使用

GROUP\u CONCAT（）

---

这条消息让我抓狂……我在原始消息中发布了新代码和错误消息。看了你提供的链接，以及其他一些与GROUP_CONCAT相关的搜索，我仍然感到困惑，

GROUP_CONCAT

之前的

SELECT

关键字在哪里？好的，已经解决了。当然会忘记一个字！！现在我只需要弄清楚如何将val_输出数组转储到csv输出中…感谢您的帮助！唉…45分钟后，我再也没有了…提示我应该做什么？

val_输出

默认用逗号分隔。你想用它做什么？

Array ( [0] => stdClass Object ( [val_output] => Altoona,PA,814.943.8112,WRTA ) )


array
  0 => 
    object(stdClass)[5]
      public 'val_output' => string 'Altoona,PA,814.943.8112,WRTA' (length=28)


Notice: Trying to get property of non-object in D:\Users\Dev\Documents\Websites\contract.dev\wp-content\plugins\custom_plugin\index_page.php on line 40

Catchable fatal error: Object of class stdClass could not be converted to string in D:\Users\Dev\Documents\Websites\contract.dev\wp-content\plugins\custom_plugin\index_page.php on line 45

SELECT GROUP_CONCAT(meta_value) val_output
FROM   wp_usermeta 
WHERE  meta_key IN ('name', 'city', 'state', 'office') AND 
        user_id = '$duser->user_id'
ORDER BY FIELD(meta_key, 'name', 'city', 'state', 'office')