Php 类别未按预期显示，有什么问题？

我有这样的分类：

我想为我已经成功创建的类别创建一个下拉菜单。但问题是，每当我单击链接时，子类别也会显示为父类别

请参见下图：

我想西部类应该只出现在服装类点击这是完美的作品，它不应该出现在点击类别链接

类别模型：

protected $fillable = [
        'name', 'parent_id'
];

public function products()
{
    return $this->belongsToMany('App\Product')->withTimestamps();
}

public function childs()
{
    return $this->hasMany('App\Category', 'parent_id', 'id');
}

在控制器中：

$category = Category::where('parent_id', '!=', '0')->with('childs')->get();

观点：

<li class="dropdown">
    <a href="javascript:void(0)" class="dropdown-toggle links-titilium" data-toggle="dropdown" role="button" aria-expanded="false">Categories <span class="caret"></span></a>
    <ul class="dropdown-menu multi-level" role="menu">
        @foreach( $category as $cat )
        <li @if($cat->childs->count()) class="dropdown-submenu" @endif>
        <a class="links-titilium" href="{{ url( '/store/category', [$cat->id, Safeurl::make($cat->name)] ) }}" @if( $cat->childs->count() ) class="dropdown-toggle" data-toggle="dropdown" @endif>
        {{ $cat->name }}
        </a>
        @if( $cat->childs->count() )
        <ul class="dropdown-menu" role="menu">
            <li>
                @foreach( $cat->childs as $child )
                <a href="{{url('/category', [Safeurl::make($cat->name), Safeurl::make($child->name)])}}">
                {{ $child->name }}
                </a>
                @endforeach
            </li>
        </ul>
        @endif
        </li>
        @endforeach
    </ul>
</li>

根据您的表格，行上方的行将获取所有类别。要获取级别为1的类别，请尝试下面的行

$category = Category::where('parent_id', '1')->with('childs')->get();

- Apparels
- Clothes
  -- Western

或者获取具有子类别的顶级类别

$category = Category::where('parent_id', null)->with('childs')->get();

- None
  - Apparels
  - Clothes
    -- Western

---

我会尝试在第一个foreach循环之后创建一个条件。它必须对整个li进行englobe处理，以便在数组位于子索引处时不会创建元素

@foreach( $category as $cat )
    @if($cat->parent_id == 1) /*this is the beginning of the if statement*/
         <li @if($cat->childs->count()) class="dropdown-submenu" @endif>
              <a class="links-titilium" href="{{ url( '/store/category', [$cat->id, Safeurl::make($cat->name)] ) }}" @if( $cat->childs->count() ) class="dropdown-toggle" data-toggle="dropdown" @endif>
                   {{ $cat->name }}
              </a>
              @if( $cat->childs->count() )
                   <ul class="dropdown-menu" role="menu">
                        <li>
                             @foreach( $cat->childs as $child )
                                  <a href="{{url('/category', [Safeurl::make($cat->name), Safeurl::make($child->name)])}}">
                                       {{ $child->name }}
                                  </a>
                             @endforeach
                        </li>
                   </ul>
              @endif
         </li>
    @endif /*this is the end of the if statement*/
@endforeach`

---

谢谢你的答复，先生。但这不是我想要的。我需要获取所有类别，包括除None类别以外的child。如果存在子类别，则不应将其显示为父类别。将立即解决您的问题。

@foreach( $category as $cat )
    @if($cat->parent_id == 1) /*this is the beginning of the if statement*/
         <li @if($cat->childs->count()) class="dropdown-submenu" @endif>
              <a class="links-titilium" href="{{ url( '/store/category', [$cat->id, Safeurl::make($cat->name)] ) }}" @if( $cat->childs->count() ) class="dropdown-toggle" data-toggle="dropdown" @endif>
                   {{ $cat->name }}
              </a>
              @if( $cat->childs->count() )
                   <ul class="dropdown-menu" role="menu">
                        <li>
                             @foreach( $cat->childs as $child )
                                  <a href="{{url('/category', [Safeurl::make($cat->name), Safeurl::make($child->name)])}}">
                                       {{ $child->name }}
                                  </a>
                             @endforeach
                        </li>
                   </ul>
              @endif
         </li>
    @endif /*this is the end of the if statement*/
@endforeach`