PHP$\u获取方法URL

可能重复：

当我进入这个链接

我得到这个错误，我不知道为什么：

Unknown column '9BYELZ0WxdQr4An' in 'where clause'

代码如下：

$sql = "SELECT * FROM chat WHERE chat_members_code = " . mysql_real_escape_string($_GET['chat_members_code']);
$chat = mysql_query($sql);
if(!$chat) {
echo mysql_error();
}else {


while($row = mysql_fetch_array($chat)) {

$chat_id = $row['id'];
$user_1_id = $row['user_1_id'];
$user_1_fullname = $row['user_1_fullname'];
$user_1_username = $row['user_1_username'];
$user_2_id = $row['user_2_id'];
$user_2_fullname = $row['user_2_fullname'];
$user_2_username = $row['user_2_username'];
$chat_body = $row['chat_body'];
$chat_members_code = $row['chat_members_code'];
$chat_time = $row['chat_time'];
$chat_date = $row['chat_date'];
$chat_datetime = $row['chat_datetime'];
}
}

---

有人知道错误在哪里吗？

您忘了用引号括起您的值：

$sql = "SELECT * FROM chat WHERE chat_members_code = '" . mysql_real_escape_string($_GET['chat_members_code']) . "'";

---

引号用于分隔字符串。您正在使用并且应该使用。这种错误说明了为什么在新的应用程序代码中不应使用mysql_查询。这太容易出错了。

$sql = "SELECT * FROM chat WHERE chat_members_code = '" . mysql_real_escape_string($_GET['chat_members_code']) . "'";