竞争编程：如何检查python列表中是否存在变量的值？

以下问题是在我的一次能力倾向测试中提出的。我尝试使用python解决。问题如下：

   COVID19 Patients are with identity numbers from 1 to 10. 
But few patients are escaped from quarantine. 
Find out those patients and write their names and details.
 Below are details of patients.

 1 Raju 
2 Ravi 
3 Lakshmi 
4 Yash 
5 Renu 
6 Tanvi 
7 Usha 
8 Vicky 
9 Rocky

10 Manu

patient=[
"Raju",
"Ravi",
"Lakshmi",
"Yash",
"Renu",
"Tanvi",
"Usha",
"Vicky",
"Rocky",
"Manu"
]

for i in range(0,):
item=input()
if item not in patient:
    print(item)

输出和输入的格式如下：

Input Format

Line 1: String
Line 2: String 
Line 3: String 
Line 4: String 
Line 5: String 
Line 6: String 
Line 7: String 
Line 8: String
Line 9: String


Constraints

None

Output Format

Line 1: String

示例输入和输出如下所示：

Sample Input 0

Raju
Ravi 
Lakshmi
Yash
Tanvi
Usha
Vicky
Rocky 
Manu

Sample Output 0

Renu

因此，我已将所有名称赋予svaed一个名为Patient[]的数组。我的问题程序如下：

   COVID19 Patients are with identity numbers from 1 to 10. 
But few patients are escaped from quarantine. 
Find out those patients and write their names and details.
 Below are details of patients.

 1 Raju 
2 Ravi 
3 Lakshmi 
4 Yash 
5 Renu 
6 Tanvi 
7 Usha 
8 Vicky 
9 Rocky

10 Manu

patient=[
"Raju",
"Ravi",
"Lakshmi",
"Yash",
"Renu",
"Tanvi",
"Usha",
"Vicky",
"Rocky",
"Manu"
]

for i in range(0,):
item=input()
if item not in patient:
    print(item)

---

您不能在

范围（0，）

上迭代，因为没有定义终点，它必须是

范围（0，len（patient））

这就是循环的外观：

for i in range(0,len(patient)):
    item=input()
    if item not in patient:
        print(item)

---

为什么要在

范围（0，）

上迭代？那是一个空范围。