Python多条件if-else语句？[已解决案件]

我有以下代码：

name = input("set name: ")
pPassWord= input("Set password: ")

if not (name == "James"):
    print("Name was wrong")
    if not (pPassWord == "Example"):
        print("Password was wrong")
    else:
    print("Name and password is wrong")
else:
    print("Name and password is right ! :) ")

怎么了

如果我设置了错误的名称=不同的James

控制台打印机是

Name was wrong 
Set Password:  

我只要

Name was wrong

试试这个：

name = input("set name: ")

if not (name== "James"):
    print("Name was wrong")
    return #exit the function if something not valid

pPassWord= input("Set password: ")
if not (pPassWord== "Example"):
    print("Password was wrong")
    return
else:
    print("Name and password is right ! :) ")

---

缩进错误，请尝试以下操作：

if not (name== "James"):
    print("Name was wrong")
    if not (pPassWord== "Example"): // due to the indentation, this now belongs to the first if-clause
        print("Password was wrong")
    else:
        print("Name and password is wrong")
else:
    print("Name and password is right ! :) ")

---

您可以在脚本顶部设置两个输入行，每个输入行后面都有一个输入行。如果您不想再次输入，当名称错误时会被询问，您必须这样做：

name = input("set name: ")
if not name == "James":
    print("Name was wrong")
else:
    pPassWord = input("Set password: ")
    if not pPassWord == "Example":
        print("Password was wrong")
    else:
        print("Name and password is right ! :) ")

请优先考虑使用IF，ELIF和其他。此链接可能有助于获取更多信息：

---

祝你好运

你的缩进是不合法的。请修复。如果要检查名称是否正确，则只需输入密码其if name！='詹姆斯。否则就会被视为另一种情况。如果你想考虑一个替代的条件，使用EIFIFE检查密码不是在其他的：所以它发生无论名称是什么。我真的很喜欢你的解决方案-但它没有解决第四个案件明确，即PrtNeNT和密码是错误的，如何返回工作？我的编辑说SyntaxError:“return”在函数外部？如何定义？你必须在函数中定义它，对吗。这是我处理这个案子的方式。谢谢@MKia！：@福普斯先生：我已经相应地修改了我的答案，我希望：-。

name = input("set name: ")
if not name == "James":
    print("Name was wrong")
else:
    pPassWord = input("Set password: ")
    if not pPassWord == "Example":
        print("Password was wrong")
    else:
        print("Name and password is right ! :) ")