Python 基于索引获取行，然后创建另一个单独的数据帧

我编写了一个代码来从数据帧中提取索引，但我不知道如何使用这些索引从原始数据帧创建另一个数据帧

是否也可以缩短我当前的代码？它相当长

编辑==

import pandas as pd

a = pd.DataFrame({"a":["I have something", "I have nothing", "she has something", "she is nice", "she is not nice","Me", "He"],
                 "b":[["man"], ["man", "eating"], ["cat"], ["man"], ["cat"], ["man"], ["cat"]]})
a = a[a.b.apply(lambda x:len(x)) == 1] # is it possible to shorten the code from here
c = a.explode("b").groupby("b")
k = ["man", "cat"]
bb = a
for x in k:
    bb = c.get_group(x).head(2).index # to here?.... this part is supposed to take the first 2 indexes of each element in k

目前的结果：

    a       b
4   she is not nice [cat]

Expected results:


    a       b
0   I have something    [man]
2   she has something   [cat]
3   she is nice [man]
4   she is not nice [cat]

首先通过筛选，然后将一个元素字符串转换为字符串，这样就可以通过测试重复性。通过

~

反转布尔掩码并通过以下方式进行过滤：

编辑：对于多个值，请使用：

---

谢谢，先生，但是我能知道“~”代表什么吗？不，它代表反转布尔掩码。对不起，先生，我犯了一个错误，已经更新了我想要找到的东西。例如，我想要的是为每个“人”和“猫”获取前2个数据。而不是为了得到复制品。

a = a[a.b.str.len() == 1]

b = a[~a['b'].str[0].duplicated()]
print (b)
                 a      b
3      she is nice  [man]
4  she is not nice  [cat]

b1 = a.groupby(a['b'].str[0]).head(2)
print (b1)
                   a      b
0   I have something  [man]
2  she has something  [cat]
3        she is nice  [man]
4    she is not nice  [cat]